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2 years ago

The ratio of boys to girls in Mr. Woods class is 5:7.

Mathematics

2 answers:

Mashcka [7]2 years ago

8 0

It’s would be approximately 25 hope that helped :)

valentina_108 [34]2 years ago

3 0

Answer:

Step-by-step explanation:

5+7 is 12, 60 divided by 12 is 5. 5x5 is 25

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In a particular country, there are two types of currency: Kabuls and Carumpts. 8 Kabuls and 2 Carumpts are worth $61.70. 3 Kabul

Misha Larkins [42]

Answer:

Kabuls = 7.5

Carumpts= 0.85

Step-by-step explanation:

Let x represent the price of kabuls

Let y represent the price of carumpts

8x + 2y= 61.70......equation 1

3x + 10y= 31.........equation 2

Multiply equation 1 by 3 and equation 2 by 8

24x + 6y= 185.1

24x + 80y= 248

-74y = -62.9

y= 62.9/74

y= 0.85

Substitute 0.85 for y in equation 1

8x + 2(0.85) = 61.70

8x + 1.7= 61.70

8x = 61.70-1.7

8x = 60

x= 60/8

x= 7.5

Hence the dollar value for kabuls is 7.5 and carumpts is 0.85

3 0

2 years ago

Find the missing factor $6.50. =$65

babymother [125]

1) $65 ÷ $6.50 = $10
2) Check Work: $10 × $6.50 = $65
$10 is your missing factor :)
Hope This Helps :)

6 0

3 years ago

Read 2 more answers

If i have 140 post its and my brother has 120 how has more

dimaraw [331]

Answer:

you

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If Ishan scored 789 out of 800 in his exams how much did he score in percentage

SOVA2 [1]

Answer:

98.6%

Step-by-step explanation:

789/800 multiplication 100% then got the answer

7 0

2 years ago

The path of a volley ball thrown over a net is modeled with the function A(x) = -0.02x2 + 0.6x + 5, where x is

LiRa [457]

Answer:

The ball travel horizontally 37 feet before it hits the ground

Step-by-step explanation:

we have

$A(x)=-0.02x^2+0.6x+5$

where

x ----> is the horizontal distance in feet

A ---> is the altitude of the ball, in feet.

we know that

When the ball hit the ground, the altitude of the ball is equal to zero

For A(x)=0

$-0.02x^2+0.6x+5=0$

solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.02x^2+0.6x+5=0$

$a=-0.02\\b=0.6\\c=5$

substitute in the formula

$x=\frac{-0.6\pm\sqrt{0.6^{2}-4(-0.02)(5)}} {2(-0.02)}$

$x=\frac{-0.6\pm\sqrt{0.76}} {-0.04}$

$x=\frac{-0.6\pm0.87} {-0.04}$

$x=\frac{-0.6+0.87} {-0.04}=-6.75$

$x=\frac{-0.6-0.87} {-0.04}=36.75$

therefore

The ball travel horizontally 37 feet before it hits the ground

3 0

3 years ago