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blagie [28]
4 years ago
8

What is the answer to this algebra problem

Mathematics
2 answers:
Sergeu [11.5K]4 years ago
5 0
The problem said : -10,8 =-2 and -15,9=-6

kiruha [24]4 years ago
4 0
First find the slope of the two coordinates.

Slope is represented by the equation:

M = y2 - y1 / x2 - x1

Substitute in the coordinates.

M = 9 - 8 / -15 - (-10)

M = 9 - 8 / -15 + 10

M = 1 / -5

M = - 1/5


Then use the equation a line:

y - y1 = m(x - x1)

y - 8 = -1/5(x - (-10)

y - 8 = -1/5(x + 10)

y - 8 = -1/5x - 2

y = -1/5x + 6 is the solution
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Write the smaller solution first and larger solution second. (X-2)(3x+3)
saw5 [17]
If this is an equation then write:
x-2=0
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3x+3=0
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so smaller solution is x= -1 and larger is x=2
4 0
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what is the equation of the line described below written in slope intercept form? the line passing through point (0,0) and parel
Diano4ka-milaya [45]
Solve <span>3x+2y-6=0 for y

2y-6=-3x

2y=-3x+6

y=-1.5x+3

So the slope of the reference line is -1.5.  For two lines to be parallel they must have the same slope so our line will also have a slope of -1.5 so we have:

y=-1.5x+b, now we can solve for b given the point (0,0)

0=-1.5(0)+b

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y=-1.5x</span>
3 0
4 years ago
3. Use a translation rule to describe the translation that is 9 units to the right and 9 units down.
larisa [96]
3. B
4. A
5. D
I believe these are the answers but if i'm wrong then crud that's "BAD". =D
8 0
4 years ago
Read 2 more answers
Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
4 years ago
The radius of a circle is 17 inches. Using the formula A ≈ 3r2, what is the approximate area of the circle?
goldfiish [28.3K]
Area = 3 x r^2 (or r squared)

= 3 x 17 x 17 = 3 x 289 = 867 square inches
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3 years ago
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