The nth term of the sequence whose integers are between 1 -7 such that there is the permission of repetition but no two consecutive digits must be even is 1.254 × 10¹¹
<h3>What are consecutive numbers?</h3>
Consecutive numbers are those numbers that succeed each other in increasing order from least to greatest. The numbers that are given:
- 1, 2, 3, 4, 5, 6, or 7 are all consecutive.
Now, suppose a (n) denotes the number of n-digit positive integers as stated in the question, thereby using:
- 1, 2, 3, 4, 5, 6, or 7 with the permission of repetition; no two consecutive digits are even.
Then, the number of n can be computed as n!
= (7!) × (6!) × (5!) × (4!) × (3!) × (2!) × (1!)
= 1.254 × 10¹¹
Learn more about consecutive numbers here:
brainly.com/question/26352026
Area is 10pi I think Bc radius is radical 10 Bc 2 radical 10/2 is radical 10. Then we do pi times radical 10 to the second power. Radical 10 to the second power is 10 Bc we remove radical when it is to the second power. Therefore, it becomes 10 times pi or 10pi
Answer:
x=5
Step-by-step explanation:
2x+2-7=5
2x-5=5
2x=10
x=5
Answer:
$41000
Step-by-step explanation:
If her salary was $1,000 more than the previous year and she save $4,200, $4,200 was 10% of her salary. So we should create an equation. (x being her salary from the previous year)
0.1(x+1000)=4200 (divide 4200 by .01)
x+100=42000
42000-1000= 41000
Answer:59
Step-by-step explanation: have a great day bro
gods coming back so dont get caught slackin