-5x - 35 = 0
-5x = 0 + 35
-5x/-5 = 35/-5
X = -7
Answer:
D
Step-by-step explanation:
Let x = total number of basketball games that was played by the team this season.
Alon started in 60% of his team’s basketball games this season. This means that he started in a total number of 60 percent of x basketball games this season.
60% of x basketball games this season = 60/100 × x
= 0.6×x = 0.6x
From the information given, Alon started a total of 12 basketball games this season. Therefore,
0.6x = 12
x = 12/0.6 = 20
Answer: 10 units
Step-by-step explanation:
Answer:
d. She should reject the null hypothesis because p < 0.10.
Step-by-step explanation:
We have a t statistic, so let's solve for the P-value on our calculators. (tcdf on a TI-84 calculator is 2nd->VARS->6.)
tcdf(left bound, right bound, degrees of freedom)
- Our left bound is t=1.457.
- Our right bound is infinity, because we're interested in the hypothesis µ>40 mg/dL. We use 999 to represent infinity in the calculator.
- Our degrees of freedom is n-1 = 15-1 = 14.
tcdf(1.457,999,14) = .084
.084 < P-value of .10, so we reject the null hypothesis.