Answer:
8% or 0.08
Step-by-step explanation:
Probability of missing the first pass = 40% = 0.40
Probability of missing the second pass = 20% = 0.20
We have to find the probability that he misses both the passes. Since the two passes are independent of each other, the probability that he misses two passes will be:
Probability of missing 1st pass x Probability of missing 2nd pass
i.e.
Probability of missing two passes in a row = 0.40 x 0.20 = 0.08 = 8%
Thus, there is 8% probability that he misses two passes in a row.
Answer:
Step-by-step explanation:
Join A and C and B and D. And add numbers to the angles formed on one of the diagonal
In triangles ABC and ADC,
Angle 1 = Angle 4
Angle 3 = Angle 2
AC = AC
Therefore, triangle ABC=ADC
Since, ABC=ADC
Similarly, triangle ABD= triangle CDB
Therefore, AB=CD and BC=DA
For
1. its
D=Days
H=Hours
M=Minutes
3d+5h+15m
3d=72h+5h
72h+5h=77h
77h+15m=77h.15m
But i only have this one right now sorry :P
The answer is 12.
Steps
If that number is x
(3+x)/(8+x)=3/4
"Cross multply"
4(3+x)=3(8+x)
12+4x=24+3x
x=12
To check: add 12 to 3 and 8. 3+12=15 and 8+12=20. 15/20=3/4