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3 years ago

5

Given the following code fragment, what is the data type of roster[9] .name? struct student { string name; double gpa; }; studen

t thisStudent; student roster[50]; string const pointer to student student double

Computers and Technology

1 answer:

SVETLANKA909090 [29]3 years ago

3 0

roster[50] is an array of "students", so roster[9] is a "student". Therefore, roster[9].name is a string.

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How does modularity provide flexibility in a structured programming design?

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Modular programming is the process of subdividing a computer program into separate sub-programs. Modularity provides flexibility in a structured programming design the following way: Modularity enables multiple programmers to work on a program at the same time. Correct answer: A

It provides developers flexibility in module maintenance.This makes the program easier to read and understand.

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3 years ago

Before creating a brief to design a product, what is needed

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A good design brief often begins with some information about the client and what their brand stands for. Including this helps to connect an individual project with the bigger picture. Aim to capture key points about what the company does, how big they are, and what their key products or services are.

Explanation:

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3 years ago

) how many bits are used for host number on the child network (subnet) , b) how many usable addresses can exist on this child ne

vovikov84 [41]

Answer:

Machine’s IP=126.127.85.170, Machine’s Netmask=/27, Parent’s Netmask=255.255.240.0 .

a) Machine's Netmask = /27 : therefore no. of remaining bits for hosts =32-27 = 5 bits.

b) No. of usable addresses in the child network = 25 -2 = 32-2 =30 [Since first(network ID of the machine) and last ip (broadcast address of the machine ) addresses are not used ]

c) first usable address is on this child network (subnet) =

First, find out the network id of machine can be found out by doing bitwise AND machine's IP and Machine's subnet mask :

01111110. 01111111.01010101.10101010 (IP)

11111111. 11111111 .11111111 .11100000 (Subnet Mask)

01111110. 01111111. 01010101.10100000 (Network ID )

first usable address is on this child network (subnet) : 01111110. 01111111. 01010101.10100001

: 126.127.85.161

d) what the last usable address is on this child network (subnet) : 01111110. 01111111. 01010101.10111110

: 126.127.85.190

e) what the child network’s (subnet's) broadcast address is :

In the directed broadcast address , all the host bits are 1. Therefore, broadcast address :

01111110. 01111111. 01010101.10111111 (126.127.85.191)

f) what the child network's (subnet's) network number is : Network ID has already been calcuulated in part c .

01111110. 01111111. 01010101.10100000 (126.127.85.160)

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3 years ago

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Answer:

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