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grandymaker [24]
3 years ago
12

Can you please explain to me how to do this please

Mathematics
1 answer:
hram777 [196]3 years ago
5 0

Explanation:

You asked how to do it, so that is the answer we will give. (The question would be "too complex" if you asked for answers to all 18 questions.)

First of all, recognize that angle values are given in degrees for some problems* and radians for other problems. Know that π radians is 180°, so you can convert to degrees by replacing π with 180°.

1. Find the quadrant of the angle:

  0 to 90° is Quadrant I

  90° to 180° is Quadrant II

  180° to 270° is Quadrant III

  270° to 360° is Quadrant IV

The signs of the trig functions in the different quadrants are ...

  sine -- positive in I and II, negative in III and IV

  cosine -- positive in I and IV, negative in II and III

  tangent -- positive in I and III, negative in II and IV

__

2. Find the reference angle. The reference angle for angle α is the smallest of ...

  |α| or |180° -α| or |360° -α|

It will be a positive number in the range 0° to 90°.

__

3. Make use of the short table of trig function values you have memorized. This gives you the exact value of the reference angle you found in step 2.

  sin(0°) = cos(90°) = 0

  sin(30°) = cos(60°) = 1/2

  sin(45°) = cos(45°) = (√2)/2

  sin(60°) = cos(30°) = (√3)/2

  sin(90°) = cos(0°) = 1

As always, the tangent is the ratio of sine to cosine, so you have ...

  tan(0°) = 0

  tan(30°) = (√3)/3

  tan(45°) = 1

  tan(60°) = √3

  tan(90°) = undefined

__

4. Apply the sign of the desired function in the desired quadrant to the value you found in step 3. (For non-zero function values, the sign on a quadrant boundary matches the signs for the quadrants on either side.)

_____

<u>Examples</u>:

  • cos(225°) = -cos(45°) = -(√2)/2 . . . . (quadrant III, ref angle 45°)
  • sec(270°) = 1/cos(90°) = 1/0 = undefined . . . . (ref angle 90°)
  • cot(5π/6) = cot(150°) = 1/-tan(30°) = -√3 . . . . (quadrant II, ref angle 30°)

_____

* Technically, sin 60 should be interpreted as sin(60 radians), since there is no degree symbol present. In <u>this</u> context, we can reasonably assume that values not a multiple of pi will be in degrees. (That may not always be the case.) <u>You</u> should always be careful to specify what unit of measure is being used for angles--<em>even if your curriculum materials are not so careful</em>. Your calculator is very particular on that point.

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Sergio plans to drive 150 miles at a rate of 60 miles per hour. He figures that it will take 25 hours. Which is NOT a reason why
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Answer:

B

Step-by-step explanation:

This is a distance-rate-time problem, so we need to use the equation: d=rt, where d is the distance, r is the rate, and t is the time.

Here, we know that the total distance is 150, so d = 150. Also, we are given that Sergio's rate is 60 mph, so r = 60. Put these in:

d = rt

150 = 60t

To solve for t, we divide both sides by 60. Because we are dividing and not multiplying, we know that B is the only one that is incorrect.

Hope this helps!

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a third grader has a goal of solving 100 math facts in 5 minutes (or 300 seconds). how many seconds can he spend on each math fa
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13.9%

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Water whose temperature is at 100∘C is left to cool in a room where the temperature is 60∘C. After 3 minutes, the water temperat
Tju [1.3M]

Answer:

21.68 minutes ≈ 21.7 minutes

Step-by-step explanation:

Given:

T=60+40e^{kt}

Initial temperature

T = 100°C

Final temperature = 60°C

Temperature after (t = 3 minutes) = 90°C

Now,

using the given equation

T=60+40e^{kt}

at T = 90°C and  t = 3 minutes

90=60+40e^{k(3)}

30=40e^{3k}

or

e^{3k}=\frac{3}{4}

taking the natural log both sides, we get

3k = \ln(\frac{3}{4})

or

3k = -0.2876

or

k = -0.09589

Therefore,

substituting k in 1 for time at temperature, T = 65°C

65=60+40e^{( -0.09589)t}

or

5=40e^{( -0.09589)t}

or

e^{( -0.09589)t}=\frac{5}{40}

or

e^{( -0.09589)t}=0.125

taking the natural log both the sides, we get

( -0.09589)t = ln(0.125)

or

( -0.09589)t = -2.0794

or

t = 21.68 minutes ≈ 21.7 minutes

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3 years ago
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