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grandymaker [24]
3 years ago
12

Can you please explain to me how to do this please

Mathematics
1 answer:
hram777 [196]3 years ago
5 0

Explanation:

You asked how to do it, so that is the answer we will give. (The question would be "too complex" if you asked for answers to all 18 questions.)

First of all, recognize that angle values are given in degrees for some problems* and radians for other problems. Know that π radians is 180°, so you can convert to degrees by replacing π with 180°.

1. Find the quadrant of the angle:

  0 to 90° is Quadrant I

  90° to 180° is Quadrant II

  180° to 270° is Quadrant III

  270° to 360° is Quadrant IV

The signs of the trig functions in the different quadrants are ...

  sine -- positive in I and II, negative in III and IV

  cosine -- positive in I and IV, negative in II and III

  tangent -- positive in I and III, negative in II and IV

__

2. Find the reference angle. The reference angle for angle α is the smallest of ...

  |α| or |180° -α| or |360° -α|

It will be a positive number in the range 0° to 90°.

__

3. Make use of the short table of trig function values you have memorized. This gives you the exact value of the reference angle you found in step 2.

  sin(0°) = cos(90°) = 0

  sin(30°) = cos(60°) = 1/2

  sin(45°) = cos(45°) = (√2)/2

  sin(60°) = cos(30°) = (√3)/2

  sin(90°) = cos(0°) = 1

As always, the tangent is the ratio of sine to cosine, so you have ...

  tan(0°) = 0

  tan(30°) = (√3)/3

  tan(45°) = 1

  tan(60°) = √3

  tan(90°) = undefined

__

4. Apply the sign of the desired function in the desired quadrant to the value you found in step 3. (For non-zero function values, the sign on a quadrant boundary matches the signs for the quadrants on either side.)

_____

<u>Examples</u>:

  • cos(225°) = -cos(45°) = -(√2)/2 . . . . (quadrant III, ref angle 45°)
  • sec(270°) = 1/cos(90°) = 1/0 = undefined . . . . (ref angle 90°)
  • cot(5π/6) = cot(150°) = 1/-tan(30°) = -√3 . . . . (quadrant II, ref angle 30°)

_____

* Technically, sin 60 should be interpreted as sin(60 radians), since there is no degree symbol present. In <u>this</u> context, we can reasonably assume that values not a multiple of pi will be in degrees. (That may not always be the case.) <u>You</u> should always be careful to specify what unit of measure is being used for angles--<em>even if your curriculum materials are not so careful</em>. Your calculator is very particular on that point.

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If the unit selling price is $2.50 and the unit cost is $1.00, what action is needed to maintain the gross margin percentage whe
REY [17]
Get the gross margin percentage of cost and multiply it to the new unit cost to get maintain the same gross margin percentage of cost.

Units Selling Price :  2.50    
Unit Cost                - <u>1.00</u>
Profit Margin          :  1.50

Gross profit margin % on sales: 1.50 / 2.50 = 0.60 x 100% = 60%
Gross profit margin % on cost : 1.50 / 1.00 = 1.50 x 100% = 150%

If the cost increase by $0.25 
Unit cost : 1.00 + 0.25 = 1.25

1.25 * 150% = 1.875 gross margin.

Gross margin + Unit Cost = Unit Price
1.875             + 1.25        = 3.125

Gross margin % on sales : 1.875 / 3.125 = 0.60 x 100% = 60%
Gross margin % on cost   : 1.875 / 1.25   = 1.50 x 100% = 150%


8 0
4 years ago
Sorry hii im dum so can someone explain this for me im so lost
sveticcg [70]

im in highschool and i have no idea

Step-by-step explanation:

8 0
3 years ago
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A shirt is 39 dolars and on sale for 33% off and what is the discount and sale price
DanielleElmas [232]
33%=0.33

33% of 39=0.33*39=12.87
discount is 12.87
minus
39-12.87=26.13


sale price=$26.13
discount=$12.87
4 0
3 years ago
Read 2 more answers
Wherever necessary.
yawa3891 [41]

Answer: 30,000

Step-by-step explanation:

5 0
3 years ago
Graph each function. Label x-axis.​
alukav5142 [94]

Answer:

Here's what I get.

Step-by-step explanation:

Question 4

The general equation for a sine function is

y = a sin[b(x - h)] + k

where a, b, h, and k are the parameters.

Your sine wave is

y = 3sin[4(x + π/4)] - 2

Let's examine each of these parameters.

Case 1. a = 1; b = 1; h = 0; k = 0

y = sin x

This is a normal sine curve (the red line in Fig. 1).

(Sorry. I forgot to label the x-axis, but it's always the horizontal axes)

Case 2. a = 3; b = 1; h = 0; k = 0

y = 3sin x

The amplitude changes from 1 to 3.

The parameter a controls the amplitude of the wave (the blue line in Fig. 1).

Case 3. a = 3; b = 1; h = 0; k = 2

y = 3sin x - 2

The graph shifts down two units.

The parameter k controls the vertical shift of the wave (the green line

in Fig. 1).

Case 4. a = 3; b = 4; h = 0; k = 2

y = 3sin(4x) - 2

The period decreases by a factor of four, from 2π to π/2.

The parameter b controls the period of the wave (the purple line in Fig. 2).

Case 5. a = 3; b = 4; h = -π/4; k = 2

y = 3sin[4(x + π/4)] - 2

The graph shifts π/4 units to the left.

The parameter h controls the horizontal shift of the wave (the black dotted line in Fig. 2).

\boxed{a = 3; b = 4; h = \frac{\pi}{2}; k = -2}}

\text{amplitude = 3; period = } \dfrac{\pi}{2}}

\textbf{Transformations:}\\\text{1. Dilate across x-axis by a scale factor of 3}\\\text{2. Translate down two units}\\\text{3. Dilate across y-axis by a scale factor of } \frac{1}{4}\\\text{4. Translate left by } \frac{\pi}{4}

Question 6

y = -1cos[1(x – π)] + 3

\boxed{a = -1, b = 1, h = \pi, k = 3}

\boxed{\text{amplitude = 1; period = } \pi}

Effect of parameters

Refer to Fig. 3.

Original cosine: Solid red line

m = -1: Dashed blue line (reflected across x-axis)

 k = 3: Dashed green line (shifted up three units)

 b = 1: No change

h = π: Orange line (shifted right by π units)

\textbf{Transformations:}\\\text{1. Reflect across x-axis}\\\text{2. Translate up three units}\\\text{3. Translate right by } \pi

6 0
4 years ago
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