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3 years ago

Why can a problem with extra information be difficult to solve?

Mathematics

2 answers:

Leni [432]3 years ago

4 0

The problems with extra information, are difficult to solve because sometimes, not all data should be used.

Therefore, students begin to doubt the fact that they are not using all the information raised in the problem.

Example:

Problem:

Suppose we have a triangle with a right angle. The problem gives us as data an angle and the sides of the triangle. We want to determine the length of the hypotenuse.

Solution:

Using the Pythagorean theorem we can solve the problem.

The given angle data is an extra information that you should not use for this case.

mart [117]3 years ago

4 0

It can be difficult to solve because the extra information can be very confusing and you may accidentally use the extra info for solving the problem, and end up getting the wrong answer

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3 years ago

Which choice is equivalent to the product below for acceptable values of x

victus00 [196]

the answer would be A.

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3 years ago

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A car drives 195 miles in 3 hours and 15 minutes. what is the average speed of the car?

g100num [7]

1 mpm or 0.0166666666 repeating mph

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3 years ago

Lúcia is using energy at a rate of 420 kilocalories (kcal) per hour (h) ice skating.

kakasveta [241]

Answer:

7000 cal/min

Step-by-step explanation:

It is mentioned that, Lucia is using energy at a rate of 420 kilo calories per hour ice skating

We know that,

1 kilo calories = 1000 calories

Using unitary method :

420 kilo calories = 420,000 calories

Also,

1 hour = 60 minutes

In this case, Lucia is using energy per 60 minutes = 420,000 calories. So,energy used by her per minute is :

$E=\frac{420000}{60} =7000 calories$

Hence, Lucia is using 7000 calories per minute.

Credit to handgunmaine: https://brainly.in/question/13030745

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%3F%7D%7B5%7D%20%2A%20%5Cfrac%7B10%7D%7B8%7D%20%3D1.5%5C%5C" id="TexFormula1" title=

Serggg [28]

Answer:

$\boxed{\sf \huge \boxed{ \sf ?} = 6}$

Step-by-step explanation:

$\sf Solve \: for \: \boxed{ \sf ?} : \\ \sf \implies \frac{\boxed{ \sf ?}}{5} \times \frac{10}{8} = 1.5 \\ \\ \sf \implies \frac{\boxed{ \sf ?} \times 10}{5 \times 8} = 1.5 \\ \\ \sf \frac{10}{5} = \frac{ \cancel{5} \times 2}{ \cancel{5}} = 2 : \\ \sf \implies \frac{ \boxed{ \sf 2} \times \boxed{ \sf ?} }{8} = 1.5 \\ \\ \sf \frac{2}{8} = \frac{ \cancel{2}}{ \cancel{2} \times 4} = \frac{1}{4} : \\ \sf \implies \frac{\boxed{ \sf ?}}{ \boxed{ \sf 4}} = 1.5 \\ \\ \sf Multiply \: both \: sides \: of \: \frac{\boxed{ \sf ?}}{4} = 1.5 \: by \: 4 : \\ \sf \implies \frac{4 \times \boxed{ \sf ?}}{4} = 4 \times 1.5 \\ \\ \sf \frac{4 \times \boxed{ \sf ?}}{4} = \frac{ \cancel{4}}{ \cancel{4}} \times \boxed{ \sf ?} = \boxed{ \sf ?} : \\ \sf \implies \boxed{\boxed{ \sf ?}} = 4 \times 1.5 \\ \\ \sf 4 \times 1.5 = 6 : \\ \sf \implies \boxed{ \sf ?} = 6$

4 0

3 years ago