1 mile = 5,280 feet
Car + space = 13.5 + 3 = 16.5 feet
5,280 / 16.5 = 320
Answer: 320 cars
Answer:
2924
Step-by-step explanation:
2752 ÷ 16 = 172 ← number of points per coin
After collecting 17 points he will have collected
2752 + 172 = 2924 points in total
Answer:
Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.
Step-by-step explanation:
Given the figure with dimensions. we have to find the area of given figure.
Area of figure=ar(1)+ar(2)+ar(3)
Area of region 1 = ar(ANGI)+ar(AIB)
![=L\times B+\frac{1}{2}\times base\times height\\\\=[1500\times (5000-2000-1500)]+\frac{1}{2}\times (3000-1500)\times (5000-2000-1500)\\\\=3375000m^2=337.5ha](https://tex.z-dn.net/?f=%3DL%5Ctimes%20B%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20base%5Ctimes%20height%5C%5C%5C%5C%3D%5B1500%5Ctimes%20%285000-2000-1500%29%5D%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%283000-1500%29%5Ctimes%20%285000-2000-1500%29%5C%5C%5C%5C%3D3375000m%5E2%3D337.5ha)
Area of region 2 = ar(DHBC)

Area of region 3 = ar(GFEH)

Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha
=987.5 ha
Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.
Let the fencing be done through x m downward from B which divides the two into equal area.
⇒ Area of upper part above fencing=Area of lower part below fencing
⇒
Hence, fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.
Answer:
1115.8
Step-by-step explanation:
The answer: x=857 and y=-401
Set up the two equations
X+2y=55
2x+y=1313
Solve the system of equations by elimination
2x+y=1313
-2x-4y=-110
Add each of the corresponding terms together
-3y=1203
Divide by -3
Y=-401
Plug y back into one of the original equations
X+2(-401)=55
X-802=55
X=857