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Vikki [24]
3 years ago
7

Based on the tiles shown, how many meters per second is equivalent to 72 kilometers per hour?

Chemistry
2 answers:
Nana76 [90]3 years ago
5 0

Answer:

The correct answer is option B.

Explanation:

Given speed of 72 km/hour.

1 kilometer = 1000 m

1 hour = 60 minutes

1 minutes = 60 seconds

1 hour = 60 × 60 seconds = 3600 seconds

72 km/h=\frac{72\times 1000 m}{1\times 3600 s}=20 m/s

= 20 m/s

72 km/h = 20 m/s

Hence, the correct answer is option B.

bija089 [108]3 years ago
3 0
We are asked to convert the value <span>72 kilometers per hour to units of meters per second. We need conversion factors to multiply to this value. We convert as follows:

</span><span>72 km / hr ( 1000 m / 1 km ) ( 1 hr / 3600 s ) = 20 m/s --->OPTION B</span><span>
</span>
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The volume  of the granite piece  in Cm³  is 12.2 cm³

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volume of granite = (volume of cylinder after placing granite - volume  of  cylinder  before  placing  granite

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convert ml  to Cm³

that is 1 ml = 1 cm³

       12.2 ml =  ? cm³

<em>by cross  multiplication</em>

=(12.2 ml x 1 cm³) / 1 ml = 12.2 cm³


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The molarity (M) of an aqueous solution containing 22.5 g of sucrose (C12H22O11) in 35.5 mL of solution is ________.
Nonamiya [84]

Answer:

1.86 M

Explanation:

From the question given above, the following data were obtained:

Mass of sucrose (C12H22O11) = 22.5 g

Volume of solution = 35.5 mL

Molarity of solution =?

Next, we shall determine the number of mole in 22.5 g of sucrose (C12H22O11). This can be obtained as follow:

Mass of sucrose (C12H22O11) = 22.5 g

Molar mass of C12H22O11 = (12×12) + (22×1) + (16×11)

= 144 + 22 + 176

= 342 g/mol

Mole of C12H22O11 =?

Mole = mass /Molar mass

Mole of C12H22O11 = 22.5 /342

Mole of sucrose (C12H22O11) = 0.066 mole

Next, we shall convert 35.5 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

35.5 mL = 35.5 mL × 1 L / 1000 mL

35.5 mL = 0.0355 L

Thus, 35.5 mL is equivalent to 0.0355 L.

Finally, we shall determine the molarity of the solution as follow:

Mole of sucrose (C12H22O11) = 0.066 mole

Volume of solution = 0.0355 L.

Molarity of solution =?

Molarity = mole /Volume

Molarity of solution = 0.066/0.0355

Molarity of solution = 1.86 M

Therefore, the molarity of the solution is 1.86 M.

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