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Vikki [24]
3 years ago
7

Based on the tiles shown, how many meters per second is equivalent to 72 kilometers per hour?

Chemistry
2 answers:
Nana76 [90]3 years ago
5 0

Answer:

The correct answer is option B.

Explanation:

Given speed of 72 km/hour.

1 kilometer = 1000 m

1 hour = 60 minutes

1 minutes = 60 seconds

1 hour = 60 × 60 seconds = 3600 seconds

72 km/h=\frac{72\times 1000 m}{1\times 3600 s}=20 m/s

= 20 m/s

72 km/h = 20 m/s

Hence, the correct answer is option B.

bija089 [108]3 years ago
3 0
We are asked to convert the value <span>72 kilometers per hour to units of meters per second. We need conversion factors to multiply to this value. We convert as follows:

</span><span>72 km / hr ( 1000 m / 1 km ) ( 1 hr / 3600 s ) = 20 m/s --->OPTION B</span><span>
</span>
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<em>A 1.70 lb sweet potato is approximately 73% water by mass. If the remaining mass is made up of carbohydrates derived from glucose (MW = 180.156 g/mol), how much carbon dioxide (MW = 44.01 g/mol) was needed to grow this sweet potato?</em>

<em />

Let's consider the following relations:

  • The potato is 100%-73%=27% glucose by mass.
  • 1 lb = 453.59 g.
  • 6 moles of CO₂ produce 1 mole of glucose.
  • The molar mass of glucose is 180.156 g/mol.
  • The molar mass of carbon dioxide is 44.01 g/mol.

Then, for a 1.70 lb potato:

1.70lbPotato.\frac{27lbGlucose}{100lbPotato} .\frac{453.59gGlucose}{1lbGlucose} .\frac{1molGlucose}{180.156gGlucose} .\frac{6molCO_{2}}{1molGlucose} .\frac{44.01gCO_{2}}{1molCO_{2}} =305gCO_{2}

<em>How much light energy does it take to grow the 1.70 lb. sweet potato if the efficiency of photosynthesis is 0.86%?</em>

<em />

According to the enthalpy of the reaction, 2802.8 kJ are required to produce 1 mole of glucose. Then, for a 1.70 lb potato:

1.70lbPotato.\frac{27lbGlucose}{100lbPotato} .\frac{453.59gGlucose}{1lbGlucose} .\frac{1molGlucose}{180.156gGlucose} .\frac{2802.8kJ}{1molGlucose} .\frac{1}{0.86\% } =3.77\times 10^{5} kJ

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