P<span>hysical characteristics are traits that on the physical body. </span>
This dissociation occur because:
O had to bond with H due to the Hydrogen bonding rule, which will form OH~ (Hydroxide).
K is more attracted to Hydroxide than Cl, so it will depart Cl and bond with OH~.
that leaves a H and a Cl, which one has a positive charge and the other has a negative, so they will bond and form Hydrochloric Acid.
Rate of reaction can be understood as the rate of change of the materials, such as the rate of depletion of the reactants or the rate of production of products. Therefore, if a graph of concentration and time is plotted, the rate of reaction is simply the slope of the graph.
First, write out a complete balanced reaction for the combustion of ethane, ethane + O2 -> CO2 + H20. Then, divide the grams of ethane by its Molar Mass and multiply by 32, the molar mass of O2.
the Calorimetry relationships you can find the amount of water in the calorimeter is m = 21.3 g
given parameters
- Lead mass M = 200.0 g
- Initial lead temperature T₁ = 176.4ºC
- Specific heat of Lead
= 0.129 J / g ºC - Sspecific heat of water
= 4.186 J / g ºC - Initial water temperature T₀ = 21.7ºC
- Equilibrium temperature T_f = 56.4ºC
to find
The body of water
Thermal energy is the energy stored in the body that can be transferred as heat when two or more bodies are in contact. Calorimetry is a technique where the energy is transferred between the body only in the form of heat and in this case the thermal energy of the lead is transferred to the calorimeter that reaches the equilibrium that the thematic energy of the two is equal
Q_{ceded} = Q_{absorbed}
Lead, because it is hotter, gives up energy
Q_{ceded} = M c_{e Pb} (T₁ - T_f)
The calorimeter that is colder absorbs the heat
Q_{absrobed} = m c_{e H_2O} (T_f - T₀)
where M and m are the mass of lead and water, respectively, c are the specific heats, T₁ is the temperature of the hot lead, T₀ the temperature of cold water and T_f the equilibrium temperature
M c_{ePb} (T₁ - T_f) = m c_{eH2O} (T_f - T₀)
m = 
let's calculate
m = 
m = 3096 / 145.25
m = 21.3 g
Using the Calorimetry relationships you can find the amount of water in the calorimeter is:
m = 21.3 g
learn more about calorimetry here:
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