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3 years ago

How do I find the rate of reaction on a graph

1 answer:

3 0

Rate of reaction can be understood as the rate of change of the materials, such as the rate of depletion of the reactants or the rate of production of products. Therefore, if a graph of concentration and time is plotted, the rate of reaction is simply the slope of the graph.

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PLZZ HELP!! If light traveling through air is then passed through glass, what is the result?

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3 years ago

When cyclopentane undergo free-radical substitution with bromine (Br2 /Heat) the product:

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Explanation:

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3 years ago

In parallel circuits, ______ follow down ______ paths.

masya89 [10]

Answer:

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3 years ago

A sample of octane undergoes combustion according to the equation 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O ΔH°rxn = -11018 kJ. What mas

Anna71 [15]

Answer:

$\large \boxed{\text{528.7 g} }$

Explanation:

It often helps to write the heat as if it were a reactant or a product in the thermochemical equation.

Then you can consider it to be 11018 "moles" of "kJ"

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r: 32.00

2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 8H₂O + 11 018 kJ

n/mol: 7280

1. Moles of O₂

The molar ratio is 25 mol O₂:11 018 kJ

$\text{Moles of O}_{2} = \text{7280 kJ} \times \dfrac{\text{25 mol O}_{2}}{\text{11 018 kJ}} = \text{16.52 mol O}_{2}$

2. Mass of O₂

$\text{Mass of C$_{8}$H}_{18} = \text{16.52 mol O}_{2} \times \dfrac{\text{32.00 g O}_{2}}{\text{1 mol O}_{2}} = \textbf{528.6 g O}_{2}\\\text{The reaction requires $\large \boxed{\textbf{528.67 g O}_{2}}$}$

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3 years ago

PLEASE HELP!!!!

coldgirl [10]

Answer:

1.2 liters.

Explanation:

Focus on the 4th digit: that's the ones column. The 3rd digit is the decimal place, just be sure to round up.

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3 years ago