All categories

2 years ago

How do I find the rate of reaction on a graph

1 answer:

3 0

Rate of reaction can be understood as the rate of change of the materials, such as the rate of depletion of the reactants or the rate of production of products. Therefore, if a graph of concentration and time is plotted, the rate of reaction is simply the slope of the graph.

You might be interested in

During a running (dynamic) compression test at idle, a good engine should produce PSI. A. 150 to 200 B. 100 to 150 C. 30 to 60 D

Mazyrski [523]

Answer:

Explanation:

7 0

3 years ago

A reaction is second order respect to the reactant A. If the reaction is 85% complete in 12 minutes, how long would it take for

AnnZ [28]

Answer:

e. 22s

Explanation:

Initial Concentration = 100

Final concentration = 15 ( Since the reaction is 85% complete)

Time = 12 minutes = 720 seconds

The integrated rate law for second order reactions is given as;

1 / [A] = (1 / [A]o) + kt

Making k subject of interest, we have;

kt = (1 / [A] ) - (1 / [A]o )

k = (1 / [A] ) - (1 / [A]o ) / t

k = [(1/ 15) - (1 / 100) ] / 720

k = (0.0667 - 0.01 ) / 720

k = 0.0567 / 720

k = 7.875e^-5

How long would it take for the reaction to be 15% complete?

Final concentration = 85 (Since the reaction would be 15% complete)

The integrated rate law for second order reactions is given as;

1 / [A] = (1 / [A]o) + kt

Making t subject of interest, we have;

kt = (1 / [A] ) - (1 / [A]o )

t = (1 / [A] ) - (1 / [A]o ) / k

t = [(1 / 85 ) - (1 / 100) ] / 7.875e^-5

t = (0.0117 - 0.01 ) / 7.875e^-5

t = 0.001765 / 7.875e^-5

t = 22.41 seconds

Corect option = E.

3 0

3 years ago

The length breadth and thickness of a brick is 18cm 8 cm and 5cm respictively find the area of the widest part of rhe brick

Sunny_sXe [5.5K]

Answer:

144cm²

Explanation:

Given dimensions:

Length x breadth x thickness

18cm x 8cm x 5cm

The widest part of this figure will be the face containing the length and the breadth.

The breadth is the width of the figure;

Area of the widest part = length x breadth = 18cm x 8cm = 144cm

The area of the widest part of the figure is 144cm²

4 0

3 years ago

How many grams of octane (C8H18) must be burned to produce 300.0g of CO2?

nika2105 [10]

Answer:

$m_{C_8H_{18}}=85.67gC_8H_{18}$

Explanation:

Hello there!

In this case, according to the given combustion reaction of octane, it is possible for us to perform the stoichiometric method in order to calculate the mass of octane that is required to consume 300.0 g of oxygen by considering the 2:25 mole ratio, and the molar masses of 114.22 g/mol and 32.00 g/mol respectively:

$m_{C_8H_{18}}=300.0gO_2*\frac{1molO_2}{32.00gO_2}*\frac{2molC_8H_{18}}{25molO_2}*\frac{114.22gC_8H_{18}}{1molC_8H_{18}} \\\\m_{C_8H_{18}}=85.67gC_8H_{18}$

Regards!

6 0

3 years ago

Is this equation balanced or unbalanced?<br> C+02=CO2

LenKa [72]

This equation is balanced

4 0

3 years ago