Answer:
Step-by-step explanation:
Given that a bag contains 40 cards numbered 1 through 40 that are either red or blue. A card is drawn at random and placed back in the bag.
This is done four times. Two red cards are drawn, numbered 31 and 19, and two blue cards are drawn, numbered 22 and 7.
From the above we cannot conclude that red cards and even numbers are mutually exclusive
Just drawing two red cards and because the two happen to be odd we cannot generalize the red cards have odd numbers.
This might have occurred due to simple chance from a comparatively large number of 40 cards.
Suppose say we have red cards 20, and 19 red 1 blue.
Then drawing 2 from 19 red cards have more probability and this can occur by chance.
So friend's conclusion is wrong.
Ahiffggggggggggggt was the morning I was going over the
This problem can be represented through the following equation
A = A₀(1/2)^t/h
where
A-----------> is the amount of substance left after time t
A₀ ----------> is the original amount---------> 2 g
h-------------> is the half-life-----------> 8 days
for A=0.04 g
t=?
0.04 = 2(1/2)^t/8
0.02 = (1/2)^t/8
Take ln on both sides:
ln(0.02) = ln [(1/2)^t/8]
ln(0.02) = (t/8)(ln 1/2)
t = 8*ln(0.02)/ln(1/2)
t = 45.15 days
the answer is 45.15 days
Answer:
From the origin, move 0.5 unit to the left along the x-axis and 1 unit vertically down, and place the point.
Step-by-step explanation:
hope this helps! :}
Answer:
x=1
Step-by-step explanation:
4 - 5(3- 2x) = -2x + 1
Distribute
4 - 15 +10x = -2x+1
Combine like terms
-11 +10x = -2x+1
Add 2x to each side
-11+10x+2x = -2x+2x +1
-11+12x = 1
Add 11 to each side
-11 +11 + 12x = 11+1
12x = 12
Divide each side by
12x/12 = 12/12
x = 1
