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Leto [7]
3 years ago
8

How many significant figures are in each underlined measurement

Mathematics
1 answer:
o-na [289]3 years ago
8 0

There should be an underline measurement or an attachment. Incomplete question

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Pls u people should help me put in this maths fast solve​
mamaluj [8]

Well, you have to ask the question first.

6 0
3 years ago
The radius of circle A is r cm. The radius of circle B is twice the radius of circle A. What difference between the circumferenc
avanturin [10]

9514 1404 393

Answer:

  2πr cm

Step-by-step explanation:

The circumference of a circle of radius r is ...

  C = 2πr

For a radius of (r cm), the circumference is ...

  A = 2π(r cm) = 2πr cm

For a radius of (2r cm), the circumference is ...

  B = 2π(2r cm) = 4πr cm

Then the difference between the circumferences is ...

  B -A = (4πr cm) -(2πr cm) = 2πr cm . . . . difference in circumference

3 0
2 years ago
An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i
Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = \sqrt{(15-x)^2+1^2}

The total time, 't', is given as follows;

t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}

The minimum value of 't' is found by differentiating with an online tool, as follows;

\dfrac{dt}{dx}  = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} =  \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }

At the maximum/minimum point, we have;

\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89

Therefore, the distance to run, x ≈ 14.96 mile

6 0
2 years ago
we do not know how much the price of a commodity is, but it has been reduced by 10% and now costs 20€. What was the starting pri
MrRissso [65]
I got 22 because if u do 20 multiplied by 10% that gives u 2 which u then add onto the 20 to get the starting price. 10% of 22 is 2 and then 22-2 = 20 (if u we’re doing it from the starting price)
4 0
2 years ago
2√64<br> (+) =8<br> 10-2 <br><br>solve 3√125=? by following steps above​
Liono4ka [1.6K]

<em><u>your </u></em><em><u>question:</u></em><em><u> </u></em>

solve 3√125=? by following steps above

<em><u>answer:</u></em>

<em>I'm</em><em> </em><em>not </em><em>sure </em><em>what</em> <em>the </em><em>steps</em><em>"</em><em> </em><em>are </em><em>but </em><em>I </em><em>got </em><em>33.54101966249 </em>

4 0
2 years ago
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