I think it could be B because it is not a 90 and it too small for an 82 but too big for a 44 and 126 is too open.
I think you mean circumference...Area is

. We have the area so we need to use it to solve for the radius which we will then use in the circumference formula.

. Divide both sides by pi to get

. Of course the simplification of the left side gives us

and r = 4. Now fill that in to the circumference formula, which is

, to get C

which is a circumference of
Answer:
y-intercept is (0,30); x-intercept is (52.5,0).
Step-by-step explanation:
Note that as x increases by 7 from -35 to -28, y decreases by 4 from 18 to 14. Thus, the slope of this line is
m = rise / run = -4/7.
Let's find the equation of the line. Start with the slope-intercept form:
y = mx + b. Use the slope m = -4/7 and the point (-28, 14) to find b:
14 = -(4/7)(28) + b, or
14 = -16 + b. Then b = 30, and the equation of the line in slope-intercept form is y = (-4/7)x + 30. The y-intercept is (0, 30).
Find the x-intercept by setting y=0 and solving the resulting equation for x:
y = (-4/7)x + 30 becomes (4/7)x = 30, and x = (7/4)(30) = 214, or 52.5.
The x-intercept is thus (52.5, 0).
The answer is A!!! Hope that helped :)
Answer:
The travel time that separates the top 2.5% of the travel times from the rest is of 91.76 seconds.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 80 seconds and a standard deviation of 6 seconds.
This means that 
What travel time separates the top 2.5% of the travel times from the rest?
This is the 100 - 2.5 = 97.5th percentile, which is X when Z has a p-value of 0.975, so X when Z = 1.96.




The travel time that separates the top 2.5% of the travel times from the rest is of 91.76 seconds.