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3 years ago

13

12. Complete the comparison: 3+7>? O A. 7 + 3 O B. 9 + 4 O C. 10-2 O D. 8 +2.

2 answers:

Elanso [62]3 years ago

7 0

For this case we must complete the following expression:

$3 + 7>$

We add the terms on the left side of the inequality:

$10>?$

We must complete the right side of inequality with one of the following options:

Option A:

$7 + 3 = 10$

We have to:

$10> 10$

It is not fulfilled!

Option B:

$9 + 4 = 13$

We have to:

$10> 13$

It is not fulfilled!

Option C:

$10-2 = 8$

We have to:

$10> 8$

Is fulfilled!

Option D:

$8 + 2 = 10$

We have to:

$10> 10$

It is not fulfilled!

ANswer:

Option C:

$10> 8$

Sever21 [200]3 years ago

3 0

Answer: C. 10-2

3+7 = 10
So you need to find which value is less than ten

A is wrong because 7+3= 10 and 10 is not less than 10
B is wrong because 9+4 = 11 and 11 is not less than 10
D is wrong because 10-2 = 10 and 10 is not less than 10

C is right because 10-2 =8 and 8 is less than 10

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2 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago

What horsepower is required to lift an 8,000 pound aircraft six feet in two minutes?

Dafna11 [192]

Answer:

The horsepower required is 235440 watt.

Step-by-step explanation:

To find : What horsepower is required to lift an 8,000 pound aircraft six feet in two minutes?

Solution :

The horsepower formula is given by,

$W=\frac{mgh}{t}$

Where, W is the horsepower

m is the mass m=8000 pound

g is the gravitational constant g=9.81

t is the time t= 2 minutes

h is the height h=6 feet

Substitute all values in the formula,

$W=\frac{8000\times 9.81\times 6}{2}$

$W=\frac{470880}{2}$

$W=235440$

Therefore, The horsepower required is 235440 watt.

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3 years ago

salantis [7]

Answer:

1 3/4 simplified or 1 12/16 not simplified

5 0

3 years ago