<span>To solve this problem, what we have to do is to divide
the whole equation 4 x^4 – 2 x^3 – 6 x^2 + x – 5 with the equation 2 x^2 +
x – 1. Whatever remainder we get must be the value that we have to subtract from
the main equation 4 x^4 – 2 x^3 – 6 x^2 + x – 5 for it to be exactly divisible
by 2 x^2 + x – 1.</span>
By using any method, I used long division we get a
remainder of -6.
Therefore we have to subtract -6 from the main equation
which results in:
<span>4 x^4 – 2 x^3 – 6 x^2 + x – 5 – (-6) = 4 x^4 – 2 x^3 – 6 x^2
+ x + 1</span>
Answer:
rational
Step-by-step explanation:
(was the comma supposed to be there?)
37 and 1/2 could mean:
37+ (1/2)
37 times 1/2
37+1/2=37 and 1/2 or 37.5
37 times 1/2=37/2=18 and 1/2=18.5
The answer to the question is 4.5
Answer:
p² -5
Step-by-step explanation:
pxp + p√ 5 -p√ 5 -√ 5√ 5
pxp -√ 5√ 5
pxp -√ 5√ 5
p² -5