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3 years ago

Find the surface area of the cylinder to the nearest whole number. The figure is not drawn to scale

Mathematics

2 answers:

julia-pushkina [17]3 years ago

7 0

Answer:

Option A is correct that is Surface Area of the Cylinder is 1659 in.²

Step-by-step explanation:

Given:

Radius of the Cylinder , r = 11 in.

Height of the Cylinder , h = 13 in.

We have to find the Surface Area of Cylinder to the nearest Whole number.

We know that,

Surface Area of the Cylinder = 2πr(r+h)

= 2 × 22/7 × 11 ( 11 + 13 )

= 2 × 22/7 × 11 × 24

= 1659.42 in.²

= 1659 in.² (nearest whole number)

Therefore, Option A is correct that is Surface Area of the Cylinder is 1659 in.²

Fynjy0 [20]3 years ago

3 0

Answer:

The best possible answer is A

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

$\sf kx (x-2)+6=0$

Expand brackets.

$\sf kx^2 -2kx+6=0$

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$\sf ax^2 +bx+c=0$

Since this is for equal roots:

$\sf b^2 -4ac=0$

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False.

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3 years ago

Is 15b+4=25.6 equivalent to 0.6+15b+4=25.6

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if explanation need comment

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