Answer:
Option A is correct that is Surface Area of the Cylinder is 1659 in.²
Step-by-step explanation:
Given:
Radius of the Cylinder , r = 11 in.
Height of the Cylinder , h = 13 in.
We have to find the Surface Area of Cylinder to the nearest Whole number.
We know that,
Surface Area of the Cylinder = 2πr(r+h)
= 2 × 22/7 × 11 ( 11 + 13 )
= 2 × 22/7 × 11 × 24
= 1659.42 in.²
= 1659 in.² (nearest whole number)
Therefore, Option A is correct that is Surface Area of the Cylinder is 1659 in.²
