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slega [8]
2 years ago
10

A man is 6 feet 3 inches tall. The tip of his shadow touches a fire hydrant that is 13 feet 6 inches away. What is the angle of

elevation from the base of the fire hydrant to the
top of the man’s head? Round to the nearest tenth of a degree.
Mathematics
1 answer:
Natalija [7]2 years ago
8 0

well, since a foot is 12inches, 6' 3" will just be 6.25' and 13' 6" will be 13.5'.

Check the picture below.

Make sure your calculator is in Degree mode.

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Two different box-filling machines are used to fill cereal boxes on an assembly line. The critical measurement influenced by the
defon

Answer:

0.1981

Step-by-step explanation:

See attachment for calculation

5 0
3 years ago
Who can solve this please
Vladimir79 [104]

Answer:

Shape 1 = l×b

= (6x²y) × (4y²)

Shape 2 = l×b

= (6x²y+2x²y)×(y²)

= (8x²y) × y²

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

8 0
3 years ago
A walkway goes through the middle of a square playground from one corner to the opposite corner. If the walkway is 20 meters lon
Dahasolnce [82]
I think you would use the Pythagorean Theorem to solve this, as a square cut across diagonally creates two isocele triangles. Since the longest side is 20 m, this value would be imputed into c^2.

a^2 + b^2 = c^2
a^2 + a^2 = 20^2
2a^2 = 400
2a^2/2 = 400/2
a^2 = 200
a = 14.14

Thus, each sides of the playground are 14.14 meters long.

7 0
2 years ago
The average fleet-wide performance of light duty trucks has made constant improvement since 1980. For example, the time for the
andrew11 [14]
A) T(m) = -0.16m +331.3

B) T(2015) = 8.9 . . . seconds

_____
The linear regression function of a graphing calculator can find the equation of the line easily. Or, you can use the 2-point form of the equation of a line.
.. T(m) = (10.5 -14.5)/(2005 -1980)*(m -1980) +14.5
.. T(m) = -0.16(m -1980) +14.5

8 0
3 years ago
State the linear programming problem in mathematical terms, identifying the objective function and the constraints. A firm makes
Sedbober [7]

Answer:

Maximum profit at (3,0) is $27.

Step-by-step explanation:

Let  quantity of  products A=x

Quantity  of products B=y

Product A takes time on machine L=2 hours

Product A takes time on machine M=2 hours

Product B takes time on machineL= 4 hours

Product B takes time on machine M=3 hours

Machine L can used total time= 8hours

Machine M can used total time= 6hours

Profit on product A= $9

Profit on product B=$7

According to question

Objective function Z=9x+7y

Constraints:

2x+3y\leq 6

2x+4y\leq 8

Where x\geq 0, y\geq 0

I equation 2x+3y\leq 6

I equation in inequality change into equality we get

2x+3y=6

Put x=0 then we get

y=2

If we put y=0 then we get

x= 3

Therefore , we get two points A (0,2) and B (3,0) and plot the graph for equation I

Now put x=0 and y=0 in I equation in inequality

Then we get 0\leq 6

Hence, this equation is true then shaded regoin is  below the line .

Similarly , for II equation

First change inequality equation into equality equation

we get 2x+4y=8

Put x= 0 then we get

y=2

Put y=0 Then we get

x=4

Therefore, we get two points C(0,2)a nd D(4,0) and plot the graph for equation II

Point  A and C are same

Put x=0 and y=0 in the in inequality equation II then we get

0\leq 8

Hence, this equation is true .Therefore, the shaded region is below the line.

By graph we can see both line intersect at the points A(0,2)

The feasible region is AOBA and bounded.

To find the value of objective function on points

A (0,2), O(0,0) and B(3,0)

Put A(0,2)

Z= 9\times 0+7\times 2=14

At point O(0,0)

Z=0

At point B(3,0)

Z=9\times3+7\times0=27

Hence maximum value of z= 27 at point B(3,0)

Therefore, the maximum profit is $27.

6 0
3 years ago
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