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zmey [24]
3 years ago
10

Ted can clear a football field of debris in 3 hours. Jacob can clear the same field in 2 hours. When they work together, the sit

uation can be modeled by the equation, where t is the number of hours it would take to clear the field together.
How long will it take Ted and Jacob to clear the field together?
Mathematics
2 answers:
Rasek [7]3 years ago
6 0

Answer:

If Ted can clear a football field of debris in 3 hours, in one hour they will have cleared 1/3 of it.

If Jacob can clear a football field of debris in 2 hours, in one hour they will have cleared 1/2 of it.

So if they work together, they will clear 1/2 + 1/3, which is 5/6, in one hour.

So the equation we get is 5/6*x = 1 and if we divide both sides by 5/6 we get that x = 1.2 hours

liraira [26]3 years ago
6 0

Answer:

\frac{6}{5} of an hour = 1 1/5 hour = 72 minutes

Step-by-step explanation:

\frac{1}{3} h + \frac{1}{2}h = 1\\\\\frac{2}{6} h + \frac{3}{6}h = 1\\\\\\\frac{5 }{6} h  =1\\\\h=\frac{6}{5}

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Ms.Terry wants to hang Christmas lights around Mr.Conner’s desk next year. His desk is 6.5 feet long and 4.3 feet wide. What is
MArishka [77]

Answer:

21.6 feet

Step-by-step explanation:

Assuming the desk is a rectangular shape, you would find the perimeter of his desk.

x = 2(6.5 + 4.3)

OR

6.5 + 6.5 + 4.3 + 4.3

=21.6

Hope this helped! :)

8 0
3 years ago
How to solve for shaded area
tamaranim1 [39]

Answer:

(a)  12.96 ft²

(b)  21.5 in²

Step-by-step explanation:

(a) For the first diagram

Area of the shaded region (A) = Area of Tripezium- area of circle

A = [1/2(a+b)h]-[πr²]............... Equation 1

Where a and b are the parallel side of the tripezium respectively, h = height of the tripezium, r = radius of the circle.

From the diagram,

Given: a = 15 ft, b = 6 ft, h = 12 ft, r = h/2 = 12/2 = 6 ft.

Constant: π = 3.14

Substitute these values into equation 1

A = [12(15+6)/2]-(3.14×6²)

A = 126-113.04

A = 12.96 ft²

(b) For the second diagram,

Area of the shaded region (A') = Area of square- area of circle

A' = (L²)-(πr²)............. Equation 2

Where L = lenght of one side of the square, r = radius of the circle

From the diagram,

Given: L = 2r = (2×5) = 10 in, r = 5 in

Substitute these values into equation 2

A' = (10²)-(3.14×5²)

A' = 100-78.5

A = 21.5 in²

5 0
3 years ago
PLEASE HELP!
Ilia_Sergeevich [38]
You have the function y= \dfrac{60x}{1+0.625x}. 
Rewrite it in the following way:

y= \dfrac{60x}{1+0.625x}=\dfrac{60x}{1+ \frac{5}{8} x}=\dfrac{480x}{8+5x}=\dfrac{96\cdot 5x}{8+5x}=
=\dfrac{96(5x+8-8)}{8+5x}=\dfrac{96(5x+8)}{8+5x}-\dfrac{96\cdot8}{8+5x}=96-\dfrac{768}{8+5x}.
This <span>function entry allows you to determine that y=96 is the horizontal asymptote and x=-8/5 is the vertical asymptote.
</span>
From the added graph of the function you can conclude that <span>the maximum number of moose that the forest can sustain at one time is 96.</span>
Answer: Correct choice is A.
<span />

8 0
3 years ago
2. A dolphin leaps 5 feet in the air at the same time an orca whale dives 12 feet below the water. How far apart are the whale a
rjkz [21]
They are 17 feet apart.
Hope this helps
5 0
3 years ago
Read 2 more answers
How would you solve this polynomial<br> Y=x^3-x^2-x-15
lisov135 [29]
I may be wrong, but it seems as if it's fully simplified...
4 0
3 years ago
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