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Fiesta28 [93]
4 years ago
9

How do you work out 5 2/3 - 2 3/4 ???

Mathematics
1 answer:
loris [4]4 years ago
6 0
Hi,
i worked out the problem and I attached the picture  

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Find 2x2 − 2z4 + y2 − x2 + z4 if x = −4, y = 3, and z = 2 can you help me
Natali [406]
Alright, so plugging it in, we get 2(-4)^2=2(2)^4+3^2-(-4)^2+2^4. Use PEMDAS with parenthesis and exponents to then get (2)(16)+9-16+16. Multiplying 1 and 16,  we get 32+41-16+16=73
8 0
3 years ago
If point A is located at (5,-7) and there are 8 points between A and B, what could be the possible coordinates for point B?
aleksandr82 [10.1K]

Answer: The possible cordinates (X,Y) of B can be found with the formula Y = √(8^2 - (X- 5)^2) - 7 where  -3 ≤ X ≤ 13

Step-by-step explanation:

The point A is located at (5, -7)

And we know that we have 8 units of difference between A and B.

The equation of a circle centerd in the point (x0, y0) is:

(x - x0)^2 + (y - y0)^2 = r2

where r is the radius of the circle

So we can draw a circle of 8 units around A, and get:

(X - 5)^2 + (Y - (-7))^2 = 8^2

So from this equation we can find all the possible values of B, for this we can isolate one of the variables in one side and get a function.

Y = √(8^2 - (X- 5)^2) - 7

So for a given value of X, you can find the value of Y. where you need to remember that (8^2 - (X-5)^2) can not be a negative number, so we must have that:

8^2 ≥ (X - 5)^2

So X can go from -3 (because (-3 - 5)^2 = 8^2)

to X = 13 (because (13 - 5)^2 = 8^2)

So X is in the range {-3, 13}

4 0
3 years ago
Read 2 more answers
Which correctly describes how to determine the measure of angle 1?
aivan3 [116]
The answer you put is correct
7 0
3 years ago
Read 2 more answers
PLEASE HELP
Studentka2010 [4]
<span>The side length for a cube 
with volume 8000cm3 = 8000^(1/3)= 20 m
Cheers,
Stan H.</span>8000=S^3<span>8000=20^3
so the answer will be B</span>
3 0
4 years ago
My brother needs help and I'm to busy so I have my phone to him please help him thank you
Vladimir79 [104]
#8 answer is A i think....
4 0
3 years ago
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