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klasskru [66]
3 years ago
10

In a clock, a large gear completes a rotation every 45 seconds, a small gear completes a rotation every 18 seconds. The gears al

igned now, how many seconds will pass before the gears are in line again?
Mathematics
2 answers:
RUDIKE [14]3 years ago
8 0
If the big gear makes 2 circles and the small gear makes 5 circles they will both be on 90 sec so it will take 90 seconds I think. My dad helped me with this one :D
sineoko [7]3 years ago
8 0

Answer:

90 seconds will pass before the gears are in line again

Step-by-step explanation:

In a clock, a large gear completes a rotation every 45 seconds.

The small gear completes a rotation every 18 seconds.

To get the number of seconds needed so these both will pass before the gears are in line again, we will simply find the LCM of 45 and 18.

45 = 3 x 3 x 5

18 = 2 x 3 x 3

LCM = 2 x 3 x 3 x 5 = 90

Hence, 90 seconds will pass before the gears are in line again

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applying row reduction process to  its associated augmented matrix:

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Now we have a simplified system:

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-3x+6y+6z=5\hspace{5 mm}(1)\\0-15y+12z=127\hspace{3 mm}(2)\\0+0+420z=1565\hspace{3 mm}(3)

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Replacing (4) in (2)

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Finally replacing (5) and (4) in (1)

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