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Vinil7 [7]
3 years ago
5

At work Keith spends one-fifth it his time in planning and buying merchandise. He spends seven-twelfths of his time in customer

service and one-twentieth of his time training the staff. This leaves him ten hours to deal with the accounts. How many hours does he work each week?
Mathematics
1 answer:
Andre45 [30]3 years ago
6 0

Answer:

60 Hours

Step-by-step explanation:

First let's get all fractions equivalent.

1/5 7/12 1/20  We can make the common denominator 60

12/60 35/60 3/60

So these three parts of his week take up 50/60 or 5/6 of his time.  That means he only has 1/6 left.  The question also tells us after all of this he only has 10 hours left, so 1/6 = 10 hours.  If you have 1/6 of something how do you find one whole?  or 6/6.  You multiply it by 6.  so 10*6 = 60, which means every week he works 60 hours.

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4 times a number less than 7 times the same number is 24. Find the number.
Afina-wow [57]

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the number is 1

Step-by-step explanation:

4(7n-n)=24

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If (-1, y) lies on the graph of y=2^2x then y=
zubka84 [21]

Answer:

y is 1/4 when x is -1 if I did interpret your equation right. Please see that I did.

I believe the equation to be y=2^{2x}.  If you meant y=2^2x, please let me know.

Thanks kindly.

Step-by-step explanation:

If (-1,y) lies on the graph of y=2^{2x}, then by substitution we have:

y=2^{2\cdot -1}.  

We just need to simplify to determine y:

y=2^{2 \cdot -1}  

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y=2^{-2}

Use reciprocal rule for exponents to get rid of the negative:

y=\frac{1}{2^2}

2^2 just means 2(2):

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y=\frac{1}{4}.

8 0
2 years ago
Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parenthe
AlekseyPX
The answer is
\frac{-6i-3}{5}.

Before we rationalize the denominator, we must simplify the numerator and denominator.  We evaluate the square root on the top, and combine like terms on the bottom:
\frac{\sqrt{-9}}{(4-7i)-(6-6i)}
\\
\\=\frac{\sqrt{9i^2}}{4-6-7i--6i}
\\
\\=\frac{3i}{-2-i}

To rationalize the denominator, we multiply by the conjugate.  The conjugate is found by making the imaginary term of the complex number, the i part, the opposite sign.  The conjugate of -2-i is -2+i:

\frac{3i}{-2-i}\times \frac{-2+i}{-2+i}
\\
\\=\frac{3i(-2+i)}{(-2-i)(-2+i)}
\\
\\=\frac{3i\times -2 + 3i\times i}{-2\times -2 + -2\times i + -2\times -i + -i\times i}
\\
\\=\frac{-6i+3i^2}{4-2i+2i-i^2}
\\
\\=\frac{-6i+3(-1)}{4-i^2}=\frac{-6i-3}{4-(-1)}=\frac{-6i-3}{5}
7 0
3 years ago
Find the gradient & y-intercept for each equation of a line.
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Answer:

4.56×223458 ×4568÷67765

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