C is the answer to this question
Answer:
3
Step-by-step explanation:
Prime factorization
36 = 3 * 3 *2 * 2
15 = 3 * 5 The biggest difference is 5 -2 = 3
<span>Think of arcsin (-1/3) as an angle, and call it "theta." The the original problem becomes "find sec [ 2 theta ]"
1 1
which is the same as "find ------------------ " or --------------------------------------
cos[2 theta] (cos theta)^2 - (sin theta)^2
Recall that theta = the angle whose sine is -1/3. Thus, sin theta = -1/3 and cos theta = 2sqrt(2) / 3.
So we now have:
1
-------------------------------------------
2 sqrt(2) -1
[------------------- ]^ 2 - [ ------- ]^2
3 3
which boils down to:
1 1
----------------- = ---------------- = 9/7 (answer)
8 1 7/9
------ - --------
9 9
</span>
Answer:
10 1/9
Step-by-step explanation:
The result to the above question is 10 1/9
