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3 years ago

14

There are 9 cherry cokes, 3 diet cokes, and 4 coke zeros in a cooler. What is the proabiliyt of selecting a drink and getting a

cherry coke, then a coke zero, without replacement?

1 answer:

Minchanka [31]3 years ago

5 0

So there are 16 cokes in total...
the probability of selecting a cherry coke is 9/16
the probability of selecting a coke zero is 4/16
for there to be no replacement I guess you could combine diet cokes with coke zero because they are both cokes..
I don't know EXACTLY how to get the probability without a replacement.. sorry

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Aloiza [94]

A=10x(15x)-p(4x)^2

A=150x^2-16px^2

A=(150-16p)x^2

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3 years ago

Rewrite each fraction in simplest form using the GCF of the numerator and denominator.

Elanso [62]

Answer:

$\sf 6. \quad \dfrac{7}{10}$

$\sf 7. \quad \dfrac{5}{17}$

Step-by-step explanation:

<h3><u>Question 6</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

42 = 2 × 3 × 7
60 = 2 × 2 × 3 × 5

42 and 60 share one 2 and one 3 in common.

Multiply them together to get the GCF: 2 × 3 = 6.

Therefore, 6 is the GCF of 42 and 60.

Divide the numerator and the denominator by the found GCF:

$\implies \sf \dfrac{42 \div 6}{60 \div 6}=\dfrac{7}{10}$

<h3><u>Question 7</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

80 = 2 × 2 × 2 × 2 × 5
272 = 2 × 2 × 2 × 2 × 17

80 and 272 share four 2s in common.

Multiply them together to get the GCF: 2 × 2 × 2 × 2 = 16.

Therefore, 16 is the GCF of 80 and 272.

Divide the numerator and the denominator by the found GCF:

$\implies \sf \dfrac{80 \div 16}{272 \div 16}=\dfrac{5}{17}$

5 0

1 year ago

Read 2 more answers

What system of equations is shown on the graph below?

erma4kov [3.2K]

Answer:

The equation of the line passing through the points (-2,0) and (0,-4)

$\frac{y - y1}{x - x1} = \frac{y2 - y1}{x2 - x1}$

$\frac{y - 0}{x - ( - 2)} = \frac{ - 4 - 0}{0 - ( - 2)} = \frac{ - 4}{2} = - 2$

$y = - 2(x + 2) \\ y = - 2x - 4$

$2x + y = - 4$

The equation of the line passing through the points (0,-2) and (4,0)

$\frac{y - y1}{x - x1} = \frac{y2 - y1}{x2 - x1} \:$

$\frac{y - ( - 2)}{x - 0} = \frac{0 - ( - 2)}{4 - 0}$

$\frac{y + 2}{x} = \frac{1}{2}$

$x - 2y = 4$

Option B

x minus 2 y = 4 and 2 x + y = negative 4

4 0

3 years ago

Read 2 more answers

Lim x--> 0 (e^x(sinx)(tax))/x^2

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

4 0

3 years ago

What is the value of x?

masya89 [10]

Answer:

Option D is correct.

Step-by-step explanation:

We can tell that

$4x + \frac{x}{2} + 2 + \frac{3x-4}{2} = 180$

Now, let's simplify.

=> $4x + 2 + \frac{4x-4}{2} = 180$

=> $4x + 2 + 2x-2 = 180$

=> $4x + 2x = 180$

=> $6x = 180$

=> $x = 30$

Therefore, Option D is correct.

Hoped this helped.

5 0

2 years ago