Li₂O
Explanation:
Elements or ions exchange their combining powers or their simplest whole number ratio during the formation of a chemical formulae of compounds.
The combining power of lithium is 1
Oxygen is 2
Lithium Oxygen
Combining
power 1 2
Exchange of
valencies 2 1
Molecular formula of the compound gives Li₂O
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Answer(s):
Template: reactants ⇒ products
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What is a chemical equation?
A chemical equation consists of the <u>chemical formulas of the </u><u>reactants</u><u> (on the left) and the </u><u>products</u><u> (on the right)</u>. The two are separated by an arrow symbol (“→” usually read aloud as “yields”). Each individual substance's chemical formula is separated from others by a plus sign.
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<span>2CO(g) + O2(g) → 2CO2(g)
from the reaction 2 mol 2 mol
from the problem 4.07 mol 4.07 mol
So 4.07 mol CO2 can be produced.
</span>
Answer:
a. Yes, it is flammable.
b. It can cause hazard and carcinogenic effect.
Explanation:
A. Yes, the vapor in the vessel is flammable because it is an organic solvent with a very low boiling point. For this reason, less energy can vaporize it. Therfore, a little high temperature or energy causes it to be very reactive and flammable.
B. - Being flammable makes it hazardous, that is, it is capable of being ignited and can burn easily, which makes it really dangerous.
- It results in carcinogenic effect on the body. Substances that cause carcinogenic effect are capable of increasing the risk of cancer. They might contain compounds that can initiate tumor.
When the temperature is high, the risk of explosion increases. Due to the fact that at higher temperature, the kinetic energy of the atoms which result in an increase in the volume and finally blasting of the vessel.
Answer:
The hydrogen produces the smaller amount of ammonia.
Step-by-step explanation:
We are given the masses of two reactants, so this is a <em>limiting reactant problem</em>.
We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 28.02 2.016 17.03
N₂ + 3H₂ ⟶ 2NH₃
Mass/g: 70.0 7.00
1. Calculate the moles of N₂ and H₂
Moles N₂ = 70.0 × 1/28.02
Moles N₂ = 2.498 mol N₂
Moles H₂ = 7.00 × 2.016
Moles H₂ = 3.472 mol N₂
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2. Calculate the moles of NH₃ from each reactant
<em>From</em> N₂:
The molar ratio is 2 mol NH₃/1 mol N₂
Moles of NH₃ = 2.498 × 2/1
Moles of NH₃ = 4.996 mol NH₃
<em>From</em> H₂:
The molar ratio is 2 mol NH₃/3 mol H₂
Moles of NH₃ = 3.472 × 2/3
Moles of NH₃ = 4.139 mol NH₃
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3. Identify the limiting reactant
The limiting reactant is H₂, because it produces fewer moles of NH₃.