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alekssr [168]
3 years ago
9

The mass numbers for two isotopes are unequal because they have different numbers of

Chemistry
2 answers:
Savatey [412]3 years ago
8 0

<u>Answer:</u> It is so because they have different number of neutrons.

<u>Explanation:</u>

Isotopes are defined as the chemical species which have same number of protons but differ in the number of neutrons.

They have same atomic number but different atomic mass.

<u>For Example:</u>  _6^{12}\textrm{C},_6^{13}\textrm{C}\text{ and }_6^{14}\textrm{C} are the three isotopes of carbon.

The number of protons in all the three isotopes is same which is 6 and the number of neutrons in the three isotopes are 6, 7 and 8 respectively.

Hence, it is so because they have different number of neutrons.

SSSSS [86.1K]3 years ago
5 0
The mass numbers for two isotopes are unequal because they have different numbers of NEUTRONS.

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3 years ago
Type in he correct values to correctly represent the valence electron configuration of oxygen
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4 years ago
Perform the following operation and express the answer in scienfific notation 7.5x10 ^9 - 2.5 x 10^8
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5 0
1 year ago
Determine the pHpH of an HFHF solution of each of the following concentrations. In which cases can you not make the simplifying
PIT_PIT [208]

The question is incomplete, complete question is :

Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? (K_a for HF is 6.8\times 10^{-4}.)

[HF] = 0.280 M

Express your answer to two decimal places.

Answer:

The pH of an 0.280 M HF solution is 1.87.

Explanation:3

Initial concentration if HF = c = 0.280 M

Dissociation constant of the HF = K_a=6.8\times 10^{-4}

HF\rightleftharpoons H^++F^-

Initially

c          0            0

At equilibrium :

(c-x)      x             x

The expression of disassociation constant is given as:

K_a=\frac{[H^+][F^-]}{[HF]}

K_a=\frac{x\times x}{(c-x)}

6.8\times 10^{-4}=\frac{x^2}{(0.280 M-x)}

Solving for x, we get:

x = 0.01346 M

So, the concentration of hydrogen ion at equilibrium is :

[H^+]=x=0.01346 M

The pH of the solution is ;

pH=-\log[H^+]=-\log[0.01346 M]=1.87

The pH of an 0.280 M HF solution is 1.87.

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3 years ago
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sertanlavr [38]

1.53

Explanation:

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