Question

A student calculated the molarity of a solution prepared by dissolving 0.730 mol of table sugar (sucrose, C12H22O11) in 1.8x10^3 mL of water as 4.06x10^-4 M C12H22O11.
Explain the student's calculation error and explain how the student should solve for the correct value of molarity. Show a valid calculation for the molarity.

II. The student then takes a 1.00 M stock solution of table sugar (sucrose, C12H22O11) and mixes 0.305 L of stock solution with additional distilled water to create a dilute solution with a total volume of 1.25 L.

Explain how the student can determine the molarity of the resulting solution. Show a valid calculation for the final molarity. PLS HELP I'M TAKING MY EXAM NOW!!!!!

Answer 1

Answer: C= 0.406 M

Explanation:

Solution.

ν

=

0.730

m

o

l

;

ν=0.730mol;

V

=

1.8

⋅

1

0

3

m

L

=

1.8

L

;

V=1.8⋅10

3 mL=1.8L;

C=0.730mol

1.8 L=0.406 M

C= 1.8L

0.730mol =0.406M

The student made a mistake because he did not convert a unit of volume from milliliters to liters. After all, molarity is defined as the number of moles of solute per liter of solution.