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gtnhenbr [62]
3 years ago
12

Which is the graph of g(x)?

Mathematics
1 answer:
olga_2 [115]3 years ago
3 0

Answer:

The last one (far right)

Step-by-step explanation:

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Which triangles are the images of JSK after preforming a reflection?
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A reflection is a form of transformation that takes each point in a figure and reflects it over a line

<h3>What is reflection?</h3>

It should be noted that a reflection is a mirror image of the shape. In this case, an image will reflect through a line, known as the line of reflection.

The figure is said to reflect the other figure, and then every point in a figure is equidistant from each corresponding point in another figure.

If A B C is the pre-image, then the triangle, A ′ B ′ C ′ is the resulting image after reflecting the triangle.

Note that an overview was given as the complete information wasn't found.

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3 0
1 year ago
4(x+5)=-6(2x+2) what the answer
Alinara [238K]

Answer:

-16x = 32

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
I am thinking of a number.if you multiply my number by 4,add 4 to the product ,and then take 1/3 of the sum, the result is 6. fi
NeTakaya

6=((X*4)+4)/3

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4 0
3 years ago
40 POINTS AND BRAINLIEST!! I NEED THIS DONE ASAP
inna [77]

(a) Answer: One solution.

Explanation: two lines that have same slope with opposite sign will necessarily cross each other at a single point, as one is "pointing uphill" and the other "downhill."

(b)  Answer: Infinitely many solutions.

Explanation:

2x + 3y = 5.5

4x + 6y = 11   | divide by 2

-->

2x + 3y = 5.5

2x + 3y = 5.5

--> equations are identical.

2x + 3y = 2x + 3y

so any (x,y) will satisfy this equation. This means infinitely many solutions.

(c) Answer: One solution

Explanation:

Continuing the two lines it becomes obvious they will cross at one point (the solution)

(d) Answer: No solution

Explanation: If the two lines are parallel, they will never cross (by definition of "parallel"). Therefore there will be no solution to the corresponding linear system.


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3 years ago
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\bf -2\left( \frac{1-5y}{7} \right)-7y=22\implies \cfrac{10y-2}{7}-7y=22&#10;\\\\\\&#10;\textit{now, let's multiply both sides by 7, to toss the denominator}&#10;\\\\\\&#10;7\left( \cfrac{10y-2}{7}-7y \right)=7(22)\implies 10y-2-49y=154&#10;\\\\\\&#10;-39y=156\implies y=\cfrac{154}{-39}\implies \boxed{y=-4}&#10;\\\\\\&#10;\textit{now, let's use that in the \underline{first one}}&#10;\\\\\\&#10;-2x-7(-4)=22\implies -2x+28=22\implies 6=2x\implies \cfrac{6}{2}=x&#10;\\\\\\&#10;\boxed{3=x}
4 0
3 years ago
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