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liraira [26]
4 years ago
11

Guy is reading a book that is 558 pages long. He reads 28 pages everyday day. How many days would it take him to finish the book

Mathematics
2 answers:
KengaRu [80]4 years ago
7 0

Answer: Approximately 20 days.

Step-by-step explanation: 558 divided by 28, is 19.92 rounding to 20.

Sedbober [7]4 years ago
3 0
20 days
divide 558 by 28 which gives you 19.9 so you round up and get 20 days
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What is the fully simplified answer to sqrt(7/18) + sqrt(5/8) - sqrt(7/2)
NeX [460]

Answer:

=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}

Step-by-step explanation:

Given expression as:

=\sqrt{\frac{7}{18}}+\sqrt{\frac{5}{8}}-\sqrt{\frac{7}{2} }

We need to simplify the given expression.

Solution:

We have:

=\sqrt{\frac{7}{18}}+\sqrt{\frac{5}{8}}-\sqrt{\frac{7}{2} }

Rewrite the expression as:

=\frac{\sqrt{7}}{3\sqrt{2}} - \frac{\sqrt{7}}{\sqrt{2}} +\frac{\sqrt{5}}{2\sqrt{2}}

\frac{\sqrt{7}}{\sqrt{2} } is a common factor to the first two terms.

Using distributive property we can factor out \frac{\sqrt{7}}{\sqrt{2} } from the first two terms.

=\frac{\sqrt{7}}{\sqrt{2}}(\frac{1}{3} -1)  +\frac{\sqrt{5}}{2\sqrt{2}}

=\frac{\sqrt{7}}{\sqrt{2}}(\frac{1-3}{3})  +\frac{\sqrt{5}}{2\sqrt{2}}

=\frac{\sqrt{7}}{\sqrt{2}}(\frac{-2}{3})  +\frac{\sqrt{5}}{2\sqrt{2}}

=-\frac{2\sqrt{7}}{3\sqrt{2}} +\frac{\sqrt{5}}{2\sqrt{2}}

\sqrt{2} is common factor, so we can factor \sqrt{2} from the above expression.

=\frac{1}{\sqrt{2} }( -\frac{2\sqrt{7}}{3} +\frac{\sqrt{5}}{2})

=\frac{1}{\sqrt{2} }( \frac{-2\times 2\sqrt{7}+3\times \sqrt{5}}{6})

=\frac{1}{\sqrt{2} }( \frac{-4\sqrt{7}+3\sqrt{5}}{6})

=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}

Therefore, we get simplified answer as.

=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}

6 0
3 years ago
Pleeeaaaase help me #16
-BARSIC- [3]
I think K=1.123
you have to find by how much it's increasing, think of 6(1/2) times WHAT equals 7(1/3)
6(1/2)a=7(1/3)
a=1.123
That means each side will be the same times 1.123
x=4.492
you can round that to 4.49 or 4.5 or 5
3 0
4 years ago
What's the probability you roll the same number twice on a regular dice?
jekas [21]
1/6 because the first number that you roll doesn't matter so it depends on the 2nd roll, in which the probability of rolling a specific number is 1/6
4 0
4 years ago
WHAT IS THE SURFACE AREA OF THE FIFURE?
max2010maxim [7]
I think the correct answer is 560ft^2.
7 0
3 years ago
An instructor in a college class recently gave an exam that was worth a total of 100 points. The instructor inadvertently made t
solniwko [45]

Answer:

B) Method 2 will increase the standard deviation of the students' scores.

Step-by-step explanation:

Given that an instructor in a college class recently gave an exam that was worth a total of 100 points.

The average score for his students was 43 and the standard deviation of the scores was 5 points.

And now he is considering two different strategies for rescaling the exam results of which:

Method 1 = Add 17 points to everyone's score.

Method 2 = Multiply everyone's score by 1.7 .

And we have to check what will be the impact of these methods on the standard deviation of the students' scores.

For this let us consider a simple example to understand this:

Firstly, Formula for calculating Standard Deviation =  \sqrt{\frac{\sum (X-Xbar)^{2}}{n-1}}

Suppose,

     X             X - Xbar       (X - Xbar)^{2}

     3              3 - 6 = -3         -3 * -3 = 9

     5              5 - 6 = -1          -1 * -1 = 1

     10            10 - 6 = 4          4 * 4 = 16

<em>Mean of above data, Xbar</em> = \frac{3+ 5+10}{3} = 6

<em>Standard Deviation of data </em>= \sqrt{\frac{26}{3-1} } = 3.6055

Now let us suppose that we multiply each value of above data with 2 so the new data will be:

     X                X - Xbar           (X - Xbar)^{2}

 3*2 = 6        6 - 12 = -6         -6 * -6 = 36

 5*2 = 10       10 - 12 = -2       -2 * -2 = 4

10*2 =20      20 - 12 = 8         8 * 8 = 64

<em>Mean of new data, Xbar </em>= \frac{6+ 10+20}{3} = 12

<em>Standard Deviation of new data</em> = \sqrt{\frac{104}{3-1} } = 7.2111

<em>Hence, we see that when we multiply any value to the data the standard deviation will increase and in other words it will multiplied by that value which value we multiplied with each data value i.e. when we multiply each data value with 2 the standard deviation also get multiplied by as </em>

  3.6055 * 2 = 7.2111

Therefore option B is correct that Method 2 will increase the standard deviation of the students' scores.

<em>And on the other hand Similarly by adding any constant to the data the Standard Deviation will remain same. Therefore Method 1 will have no impact on standard deviation of the students' scores.</em>

8 0
3 years ago
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