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jeyben [28]
3 years ago
12

Atriangle was translated 4 units down.

Mathematics
2 answers:
loris [4]3 years ago
7 0

Answer:

Idk if this is right but I think it's The transformed shaped shifted 7 units to the right so add 7 to x and it shifted 6 units down so subtract 6 from y.

The answer is (x,y) = (x+7) (y-6)

Hope this helps!!!?

katrin2010 [14]3 years ago
7 0

Answer:

it's B

i hope this helps

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14w^9- 19w^9<br> Help please
zhuklara [117]

Answer:

-5w^9.

Step-by-step explanation:

These two terms are what we call, 'like terms'. This means that they are terms whose variables and exponents are the same. 14w^9- 19w^9 have the variable w^9 in common.

In these cases, all we do is use the coefficients (the number in front of the variable). Hence, 14w^9- 19w^9, quite literally turns into, 14-19. If we complete the sum, 14-19= -5. Put it all together, we have -5w^9.

Hope this helps!

4 0
3 years ago
BIG POINT FOR WHOEVER HELPS ME! PLEASE!!!!!Simplify and determine the coefficient of (-2/3X)(3Y).-X)
rewona [7]
You multiply like terms first, which means -2/3x*-x. It becomes 2/3x*3y. The coefficient of x is 2/3. The coefficient of y is 3. You can’t combine them because they are not like terms with the variables.
6 0
3 years ago
Use properties of exponents to rewrite the following expressions as a number or an exponential expression with
Lerok [7]

Answer:

[(2)^√3]^√3 = 8

Step-by-step explanation:

Hi there!

Let´s write the expression:

[(2)^√3]^√3

Now, let´s write the square roots as fractional exponents (√3 = 3^1/2):

[(2)^(3^1/2)]^(3^1/2)

Let´s apply the following exponents property: (xᵃ)ᵇ = xᵃᵇ and multiply the exponents:

(2)^(3^1/2 · 3^1/2)

Apply the following property of exponents: xᵃ · xᵇ = xᵃ⁺ᵇ

(2)^(3^(1/2 + 1/2)) =2^3¹ = 2³ = 8

Then the expression can be written as:

[(2)^√3]^√3 = 8

Have a nice day!

7 0
3 years ago
Please simplify this fraction c:
Liula [17]
F you just want to see the really short way, just skip down to AAAAAAAAAAAA

so, here is the long explanation
exponential properties
x^{-m}= \frac{1}{x^m}

don't forget pemdas
2x^2=2(x^2)

so
\frac{2x^{-4}}{3xy}=\frac{2 \frac{1}{x^4} }{3xy}=  \frac{2}{3x^5y}


AAAAAAAAAAAAAAAAAAAAAAAA
so we see
the original equatio is
\frac{2x^{-4}}{3xy}

remember
\frac{ab}{cd} =( \frac{a}{c})( \frac{b}{d})

so we can seperate the constants
\frac{ab}{cd} =( \frac{2}{3})( \frac{x^{-4}}{xy})

we know that the placeholders cannot affet the position of the constants unless they are grouped together which they are not

terfor the answer must have 2/3 in it

the only one that hsa that is A


ANSWER IS A
3 0
3 years ago
Read 2 more answers
The graph shows the cost, C, of sending m text messages. What is the cost per message?
Travka [436]

Answer:

C.$0.15 I TOOK IT ON STUDY ISLAND

Step-by-step explanation:

First, you want to find an exact point on the graph.  What I mean by this is you want to go somewhere on the graph where the line goes through an exact y and x value.

Second, you want to figure out where this x and y value are.  Where the graph first goes through two points is at (20, 3).

Third, you want to figure out what the 20 and the 3 mean.  20 is the number of messages and 3 is the dollar amount.

Finally, to calculate the amount of money per message, you divide the dollar amount (3) by the number of messages (20).  So, you have 3/20.  After this, simplify 3/20 to get 0.15, or 15 cents per message.

3 0
3 years ago
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