The solution to the problem is as follows:
<span>you have"a" as common so, you can write it as: a(3b+1) +3b^2 + b. from the remaining two terms, you have b common, so write it as a(3b+1) +b(3b+1).
This gives you (a+b)(3b+1)
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Answer:
ok so i am going to give you a litle saying to help you remember the way it goes ok. this problem is in slope-intercept form
"y=mx+b,,b is my y-intercept you'll see,m is my slope which is rise over run"
so if -4 is your slope it will go where the m is in the formula y=mx+b so it would now be y=-4x+b and then the b is your y-intercept so 3 would go where the b is in the formula now now since we plugged in all the parts.
<u>the answer is y=-4x+3 </u>
Step-by-step explanation:
It would mean for them to. Sooo like One of the basic forms they would use for the internet will help over however many people work there. If median and mode is 25 you would want to set the numbers together
.... hope this helps?
Answer:
12 units
Step-by-step explanation:
To find any side length of a right triangle given two side lengths, you would use the pythagorean theorem which is a² + b² = c². In this equation, a and b represents either the height of base of the triangle, and c represents the hypotenuse of the triangle (the diagonal line - in your question it is 13). By plugging in the base and hypotenuse, you get the equation of 5² + b² = 13². 5² is equal to 25 and 13² is equal to 169, so the equation is 25 + b² = 169. Subtract 25 for both sides of the equation and you find that b² = 144. Square both sides and the missing length is 12 because √144 = 12.
For the first one:tick the second to last.
for the second: tick the first circle.
for the third: tick the second to last.
for the forth: tick the second.
for the fifth: tick the last.
for the last one: tick the second.
Hope it helps...
