Given: ∆AKL, AK = 9 m∠K = 90° m∠A = 60° Find: P∆AKL The area of ∆AKL
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We have the rational expression 
; to simplify it, we are going to try to find a common factor in the numerator, and, if we are luckily, that common factor will get rid of the denominator 
.
Notice that in the denominator all the numbers are divisible by two, so 2 is part of our common factor; also, all the terms have the variable
, and the least exponent of that variable is 1, so will be the other part of our common factor. Lets put the two parts of our common factor together to get .
Now that we have our common factor, we can rewrite our numerator as follows:
We are luckily, we have in both numerator and denominator, so we can cancel those out:
We can conclude that the simplified version of our rational function is
.
Notice that in the denominator all the numbers are divisible by two, so 2 is part of our common factor; also, all the terms have the variable
Now that we have our common factor, we can rewrite our numerator as follows:
We are luckily, we have
We can conclude that the simplified version of our rational function is
