Answer:
![(-7,4]\text{ or }\{x|-7](https://tex.z-dn.net/?f=%28-7%2C4%5D%5Ctext%7B%20or%20%7D%5C%7Bx%7C-7%3Cx%5Cleq%204%5C%7D)
Step-by-step explanation:
The domain is the span of x-values covered by the function.
From the graph, we can see that the graph covers all the x-values from x=-7 to x=4.
However, note that closed and open circles. There is an open circle at x=-7, which means that the domain excludes x=-7. However, the circle at x=4 is closed, meaning it is included in the domain.
Therefore, the domain is, in interval notation:
![(-7,4]](https://tex.z-dn.net/?f=%28-7%2C4%5D)
We use parentheses on the left because we do not include -7. And we use brackets on the right because we <em>do </em>include the 4.
And in set notation, this is:
Answers:
A. 6 Large taxis = 42 seats 9 Small taxis = 36 seats = 78 seats in total
B. 6 Large taxis = $498 + 9 Small taxis = $450 498+450= $948
C. 5 Large taxis and 10 Small taxis
Step-by-step explanation:
A. 6 Large taxis = 42 seats 9 Small taxis = 36 seats = 78 seats in total
If I did 8 small taxis the total number of seats would be 74, so I did one small taxi more to make it fair. There would be seats for everyone but 3 seats extra
B. 6 Large taxis = $498 + 9 Small taxis = $450 498+450=948
C. 5 Large taxis and 10 Small taxis
While the more small taxis there are, the more cheaper it is for Max but the less seats there would be for 75 people, So I did 1 more small taxi and 1 less large taxi.
The total number of seats now is 75 seats which is perfect amount for 75 people
So the total cheaper cost would $915 while still maintaining a fair amount of seats which is 75
Answer:
Step-by-step explanation:
<em>Given:</em>
Mn is diameter of circle having centre O
and BD = OD,
<em><u>To prove that:</u></em>
<u>
</u>
<em>Solution:</em>
Join the points O and B and draw OB,
On joining the line,
in ∆OCD and ∆OBD,
OC =OB → (Radius of same circle)
BD =CD → (from given)
OD =OD → (Common side in both the triangles)
Hence ∆OCD and ∆OBD are congruent from SSS property.
so we can say that,
Consider above prove as statement A
Corresponding angles of congruent traingle.
in ∆ OAB,
OA = OB (radius of same circle)
hence ∆OAB is an isosceles traingle.
We know that opposite angle of isosceles traingle are always equal. hence,
Consider above prove as statement B
From Statement A & B we can say that
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