Answer:
the answer you have is correct
Answer:
See proof below.
Step-by-step explanation:
True
For this case we need to use the following theorem "If 
are eigenvectors of an nxn matrix A and the associated eigenvalues 
are distinct, then 
are linearly independent". Now we can proof the statement like this:
Proof
Let A a nxn matrix and we can assume that A has n distinct real eingenvalues let's say 
From definition of eigenvector for each one 
needs to have associated an eigenvector 
for 
And using the theorem from before , the n eigenvectors 
are linearly independent since the 
are distinct so then we ensure that A is diagonalizable.
Answer:
convert kisme krna h binary ki bicimal
binary me to 1011001 hota h.....
Distribute
remember a(b+c)=ab+ac
8(y+4)=8(y)+8(4)=8y+32
8y+32=7y+38
minus 7y both sides
y+32=38
mius 32 oth sides
y=6
