Question

Solve the inequality. Graph the solution set. 26 + 6b 2(3b + 4)

Answer 1

The inequality is : 26 + 6b= 2(3b + 4)
On opening the bracket we get,
or 26 + 6b= 6b + 8
Now, bring the variable terms to right hand side,
or 26 + 6b - 6b = 8
or 26 = 8, which is not possible because 26 can never be equal to 8.
Thus, this inequality has no solutions. 

Answer 2

we have

$26 + 6b\geq2(3b + 4)$

Applying the distributive property on the right side

$26 + 6b\geq6b+8$

subtract $6b$ from both sides

$26\geq 8$ -------> is true

for all real numbers the inequality is true

therefore

the graph is a shaded area everywhere.

the answer is

the solution is all real numbers