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viktelen [127]
3 years ago
12

A randomly generated password contains four characters. Each of the four characters is either a lowercase letter or a digit from

0–9. Each character in the password cannot be used more than once.
HELP QUICKLY PLEASE
What is the approximate probability that exactly one of the four characters will be a number?

1%
11%
28%
44%
Mathematics
2 answers:
kicyunya [14]3 years ago
8 0

The correct answer is:

C. 28%

The approximate probability that exactly one of the four characters will be a number is 28%.

|Huntrw6|

juin [17]3 years ago
6 0
Sample space is 36C4
Now, we want to know all of the combinations that have 1 digit in it.
So, we can have one here:

1XXX
X1XX
XX1X
XXX1

But we have 10 different digits to choose from. So, we need to introduce the combination term, nCr, where n is a list of all digits and r is how many we want.

Since we only want one, we will need 10C1 for the number of digits. But we need to choose three lowercases, so it becomes 10C1 × 26C3

Since it's a probability question, we need to divide that by our sample space, 36C4, and our percentage becomes 44%
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Answer:

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2 years ago
Please help me<br> Solve for x.<br> a) 30<br> b) 27<br> c) 33
OlgaM077 [116]

Answer:

x = 27

Step-by-step explanation:

The angle at any point on a straight line is 180 degrees.

The middle line over there is creating a right angle which is 90 degrees.

This must mean that both sides are 90 degrees.

3x+9 = 90

3x = 81

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3 years ago
What are the solutions to the system of equations? y=2x^2−6x+3 y=2x+3
adoni [48]

Answer:

Step-by-step explanation:

y=2x²-6x+3

y=2x+3

2x²-6x+3=2x+3

2x²-6x+3-2x-3=0

2x²-8x=0

2x(x-4)=0

x=0,4

y=0+3=3

and y=2(4)+3=11

so solutions are (0,3) and (4,11)

5 0
3 years ago
You are arguing over a cell phone while trailing an unmarked police car by 25 m; both your car and the police car are traveling
BARSIC [14]

Answer:

  (a) 15 m

  (b) ground speed: 26.14 m/s (94.1 km/h); relative speed 12 m/s

Step-by-step explanation:

We can choose the frame of reference to be the trailing car. We can start counting time from the point the lead car begins deceleration. Then its position (in meters) relative to the trailing car is ...

  d(t) = 25 - 5/2t² . . . . . . where 25 m is the initial distance and -5 is the acceleration in m/s².

(a) Then the distance between cars at t=2 is ...

  d(2) = 25 - (5/2)·4 = 15 . . . . meters

__

(b) The <em>relative velocity</em> at 2.4 seconds is ...

  d'(t) = -5t

  d'(2.4) = -5(2.4) = -12.0 . . . m/s

The closure speed with the police car is 12 m/s.

__

We need to do a little more work to find the ground speed of the trailing car when the cars bump.

The distance between the cars at t=2.4 seconds is ...

  d(2.4) = 25 -(5/2)2.4² = 10.6 . . . . meters

At the closure speed of 12 m/s, it will take an additional ...

  10.6 m/(12 m/s) = 0.8833... s = 53/60 s

to close the gap. The speed of the trailing car at that point in time will be the original speed less the deceleration for 0.8833 seconds:

  (110 km/h)·(1/3.6 (m/s)/(km/h))-(5 m/s²)(53/60 s)

     = 26 5/36 m/s = 94.1 km/h

_____

<em>Comment on following distance</em>

To avoid collision, the trailing car must be trailing by at least the distance it covers in 2.4 seconds, about 73 1/3 meters.

6 0
3 years ago
An art teacher buys 9 bags of cotton balls there are 68 cotton balls in each bag whitch expression is best to estimate the numbe
Phantasy [73]

Answer:

612

Step-by-step explanation:

9 x 68 = 612

8 0
3 years ago
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