The cross-sectional area parallel to the bases of the two figures above is the same at every level. Find the volume of the cone,
to the nearest tenth.
A.
26.5 cm3
B.
44.2 cm3
C.
79.5 cm3
D.
132.5 cm3
A.
26.5 cm3
B.
44.2 cm3
C.
79.5 cm3
D.
132.5 cm3
2 answers:
Answer:
B. 44.2 cm3
Step-by-step explanation:
we know that
If the cross-sectional area parallel to the bases of the two figures above is the same at every level
then
the area of the base of the triangular pyramid is the same that the area of the base of the cone
step 1
Find the area of the base of the pyramid
step 2
Find the volume of the cone
The volume of the cone is equal to
we have
substitute
You might be interested in
- If x = 5 is a zero of the given polynomial, then,
- (x - 5) is a factor of the polynomial. [Since, x = 5 or, x - 5 = 0]
- Now, divide the polynomial with (x - 5) using long division method. (See the picture)
- We get (x^2 - x - 6) as the quotient.
- Now, factorise the above polynomial:
- (x^2 - x - 6)
- = (x^2 - 3x + 2x - 6)
- = x(x - 3) + 2(x - 3)
- = (x - 3)(x + 2)
- Therefore, x^3 − 6x^2 − x + 30 = (x − 5)(x − 3)(x + 2)
<u>Answer</u><u>:</u>
<u>B.</u><u>(x − 5)(x − 3)(x + 2)</u>
Hope you could get an idea from here.
Doubt clarification - use comment section.
