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3 years ago

10

i have 16 red skittles, 15 green skittles, 10 yellow skittles, 11 purple skittles, and 11 orange skittles. What fraction of my s

kittles are red?

2 answers:

larisa [96]3 years ago

8 0

I think the answer is 16/63

Ainat [17]3 years ago

7 0

16/63 is the answer

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Which expression is equivalent to the algebraic expression below 3(-2x-1)

stiv31 [10]

Answer:

I think you are missing the image

Step-by-step explanation:

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2 years ago

Read 2 more answers

What is the mean of each question?

Serhud [2]

Formula for finding mean:

Mean = (a1 + a2 + ... + an) / n

Mean is another word for average; average number of a data set.

Problems with steps:

---------------------------------------------------------------------------------------

1) 9, 3, 6

Average = Sum/Count

Sum = 18/6

Count = 3

2) 14, 12, 17, 9

52/4

Mean = 13

3) 15,8,10,5,7

= 45/5

Mean = 9

4) 18,19,11

= 48/3

Mean = 16

5) 4,20,16,4

= 44/4

Mean = 11

6) 12,11,12,20,15

= 70/5

Mean= 14

7) 19,8,3

= 30/3

Mean = 10

8) 7,13,6,2

= 28/4

Mean = 7

9) 12,15,17,2,14

60/5

Mean = 12

10) 10,18,8

= 36/3

Mean = 12

11) 5,2 ,0,1

= 8/4

= 2

12) 3,9,5,16,7

= 40/5

Mean = 8

SOLVED !

Hope this helps!

- ROR

7 0

2 years ago

Given f(x)=x^2+5 and g(x)=2x^3-1 find (f/g)(-3)

AlekseyPX

For this case we have the following functions:

$f (x) = x ^ 2 + 5\\g (x) = 2x ^ 3-1$

By definition of composition of functions we have:

$(f / g) (x) = \frac {f (x)} {g (x)}$

Then substituting:

$f (-3) = (- 3) ^ 2 + 5 = 9 + 5 = 14\\g (-3) = 2 (-3) ^ 3-1 = 2 (-27) -1 = -54-1 = -55$

So:

$(f / g) (- 3) = \frac {14} {- 55} = - 0.25$

Answer:

$(f / g) (- 3) = \frac {14} {- 55} = - 0.25$

7 0

2 years ago

IrinaVladis [17]

Answer:

We know that a negative value is positive of all even exponents and negative for all odd exponents.

y=(-1)^x

5 0

3 years ago

A study suggested that childrenbetween the ages of 6 and 11 in the US have anaverage weightof 74 lbs. with a standard deviation

Doss [256]

Answer:

The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A study suggested that children between the ages of 6 and 11 in the US have an average weightof 74 lbs, with a standard deviation of 2.7 lbs.

This means that $\mu = 74, \sigma = 2.7$

What proportion of childrenin this age range between 70 lbs and 85 lbs.

This is the pvalue of Z when X = 85 subtracted by the pvalue of Z when X = 70. So

X = 85

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{85 - 74}{2.7}$

$Z = 4.07$

$Z = 4.07$ has a pvalue of 1

X = 70

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{70 - 74}{2.7}$

$Z = -1.48$

$Z = -1.48$ has a pvalue of 0.0694

1 - 0.0694 = 0.9306

The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.

7 0

2 years ago