Four times the quantity of x minus five is equal to three times the quantity of x plus two
f(n) is the nth term
Each term f(n) is found by adding the terms just prior to the nth term. Those two terms added are f(n-1) and f(n-2)
The term just before nth term is f(n-1)
The term just before the (n-1)st term is f(n-2)
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For example, let's say n = 3 indicating the 3rd term
n-1 = 3-1 = 2
n-2 = 3-2 = 1
So f(n) = f(n-1) + f(n-2) turns into f(3) = f(2) + f(1). We find the third term by adding the two terms just before it.
f3) = third term
f(2) = second term
f(1) = first term
Answer:
y = 3x + 8
Step-by-step explanation:
y = mx + b
m is the slope
b is the y intercept
Let point P be with coordinates
Find the equation of the tangent line.
1. If
then 
2. The equation of the tangent line at point P is

Find x-intercept and y-intercept of this line:
- when x=0, then

- when y=0, then

The area of the triangle enclosed by the tangent line at P, the x-axis, and y-axis is

Since point P is on the parabola, then
and

Find the derivative A':

Equate this derivative to 0, then

And

Answer: two points: 
Answer:
22.50
Step-by-step explanation:
0.75 x 30 years of mortgage