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dlinn [17]
3 years ago
7

Find an equation of the line passing through each of the following pairs of points.

Mathematics
1 answer:
julia-pushkina [17]3 years ago
3 0

For this graph the equation is x= -3

Because in the coordinates you gave, all the x values are -3 telling me that the line is a straight vertical line passing through the -3 x-axis and has no y-intercept as it's a vertical line, not diagonal, so it's not passing through the y-axis. Plus because of this too this line has no gradient.

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A student solved 6x+4=2(x−8) in four steps as shown:
mr_godi [17]
The first thing you should do is solve the equation yourself.

1) Distribute the 2.  
6x + 4 = 2x – 16

2) Next, you'll want to get the x's on one side. So add -2x to both sides.
6x + 4 + -2x = 2x + -2x - 16
4x + 4 = -16

3) Now subtract 4 from both sides
4x + 4 – 4 = -16 – 4
4x = -12

4) Finally, divide both sides by 4
4x/4 = -12/4
x = –3

To solve this problem all you need to do is look back out you work, and figure out the correct solution. The answer the question is The student made an error in Step 1.

7 0
3 years ago
4. Find the vertex, focus, and directrix of the parabola. Sketch its graph, showing the focus and the directrix.
valentina_108 [34]

Answer:

vertex - (0,0)

focus - (0, 3/4)

directrix - 3/4

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graph of equation:

8 0
2 years ago
Brianna has $50 in her bank account. She pays $6 to attend her school football game. She wants to buy hotdogs for her and her fr
sattari [20]

Answer:

12

Step-by-step explanation:

$50-6 (ticket to game) = 44 - $20 (the balance she wants to have left) = $24.

$24/2=12 (amount of hotdogs she can buy)

6 0
2 years ago
Help will name brainliest
liberstina [14]

\text{For angle N,}\\\\PQ= \text{Perpendicular.}\\\\QN = \text{Hypotenuse.}\\\\\text{Now,}\\\\\sin N = \dfrac{\text{Perpendicular}}{\text{Hypotenuse}}\\\\\\~~~~~~~=\dfrac{QP}{QN}

5 0
1 year ago
Find the value of each variable
mina [271]

Answer:

x = 16  y= 16√3

Step-by-step explanation:

we know that a angle is 60 degrees. Thanks to this information we can say that x is half the hypothenuse, so is value is 16.

y can be express as √3/2 x 32 = 16√3

7 0
2 years ago
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