4 years ago

Is this a function????????

Mathematics

1 answer:

Vsevolod [243]4 years ago

5 0

This is not a function because it does not pass the vertical line test.

Hope this helps!!
~Kiwi

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$f(x) = 2[\frac{3^x}{9}] + 2$

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Step-by-step explanation:

Given

$f(x) = 2(3)^{x-2} + 2$

$f(x) = \frac{1}{2}(4)^{x+2}$

Required

Remove the h component

In a function, the h component is highlighted as:

$f(x) = a^{x+h}$

So, we have:

$f(x) = 2(3)^{x-2} + 2$

Split the exponents using the following law of indices:

$a^m/a^n = a^{m-n}$

$f(x) = 2*\frac{3^x}{3^2} + 2$

$f(x) = 2*\frac{3^x}{9} + 2$

$f(x) = 2[\frac{3^x}{9}] + 2$

<em>The h component has been removed</em>

$f(x) = \frac{1}{2}(4)^{x+2}$

Split the exponent using the following law of indices

$a^{m+n} =a^m * a^n$

So, we have:

$f(x) = \frac{1}{2}(4)^x * 4^2$

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$f(x) = \frac{1}{2}(4)^x * 16$

Divide 16 by 2

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3 years ago