Answer:
0.
Step-by-step explanation:
Answer:
The area of ∆DEF = 4.5in²
Step-by-step explanation:
From the above diagram,
∆BAC ~∆DEF
It is important to note that if two triangles are similar, the ratio of their areas is equal or equivalent to the ratio of the areas of their sides
This means for the above question, that
We have the bigger triangle = ∆BAC has a side of 4 in and Area = 8 in²
The small triangle has a side of 3in
Finding the scale factor k = ratio of the sides of both Triangles
k = 4/3
k² = (4/3)²
k² = 16/9
Hence,
Area of ∆BAC/ Area of ∆DEF = 16/9
8in²/Area of ∆DEF = 16/9
We cross Multiply
8 in² × 9 = Area of ∆DEF × 16
Divide both sides by 16
Area of ∆DEF = 72/16
= 4.5in²
Therefore, the Area of ∆DEF rounded to the nearest tenth = 4.5in²
Answer:
C) 1/7
Step-by-step explanation:
so idk what the formula is called but it looks like this:
y2-y1/x2-x1 and if you plug in the numbers then you'll get the answer
3 - 4/-1 - 6 = -1/-7 = 1/7
you can also switch the numbers your answer will always be the same
4 - 3/6 - (-1) = 1/7
so the answer is c
That is a tenth degree equation.
The degree of an equation is the highest power it contains.
Let's write the parametric line
(x,y,z) = (0,2,8) + t(5,-1,4)
(5,-1,4) is called the direction vector of the line. It's normal to the plane
5x - y + 4z = constant
We get the constant by substituting the point (3,0,7),
5x - y +4z = 5(3) - 0 + 4(7) = 43
5x - y +4z = 43
