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2 years ago

10

A large cell phone company would like to know if their clients are happy with the service they provide . Which of the following

methods would be the best for choosing a random sample that is a fair representation of their clients?

1 answer:

Aleksandr-060686 [28]2 years ago

7 0

Answer:

2nd option. this provides an unbiased way to choose the clients surveyed.

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Find which term in the geometric sequence 1,3,9,27,... is the first to exceed 7,000.

Zielflug [23.3K]

The common ratio between terms is 3, so the sequence has general $n$ -th term

$a_n=3^{n-1}$

for $n\ge1$ . The term exceeds 7000 when

$3^{n-1}>7000\implies n-1>\log_37000\implies n>1+\log_37000\approx9.06$

which means the first time $a_n$ exceeds 7000 occurs when $n=10$ . Indeed,

$a_{10}=3^{10-1}=19,683$

while the previous term would have been

$a_9=3^{9-1}=6561$

8 0

3 years ago

The sum of three consecutive odd integers is 69. find the integers

Marta_Voda [28]

Let the integers be x-2, x, x+2.

Given,

x -2 + x + x + 2 = 69

3x = 69

x = 23

Hence, the integers are 21, 23 and 25.

6 0

2 years ago

Is there some one who can help me please

lesya692 [45]

Answer:

I'd say $18

Step-by-step explanation:

I cant really tell, but your best guess is $18

6 0

3 years ago

Please help asap!! will give brainlist :)

Naddik [55]

Yo sup??

Area of trapezium=1/2*(sum of opposite sides)*(height of trapezium)

=1/2*(12.5+17.5)*6

=1/2*30*6

=90 cm²

Therefore the correct answer is option A

Hope this helps.

8 0

3 years ago

Read 2 more answers

2.7 (7.8)??? I don't know how to work this problem...

ruslelena [56]

Just multiply the two, your answer should be 21.06

8 0

3 years ago

Read 2 more answers