Yes they are congruent because both of them are equilateral triangles
Answer:
0.435897 km per minute
Step-by-step explanation:
Set Events:
T=tests positive~T=tests negativeP=subject is pregnant~P=subject is not pregnant
We are givenP(T n ~P)=0.02P(~T n P)=0.03P(P)=0.7
recall by definition of conditional probabilityP(A|B)=P(A n B)/P(B)
Need to find P(P|~T)
First step: make a contingency diagram of probabilities (intersection, n)
P ~P sum
T 0.67 0.02 0.69=P(T)
~T 0.03 0.28 0.31=P(~T)
sum 0.70 0.30 1.00
=P(P) =P(~P)
therefore
P(P|~T)=P(P n ~T)/P(~T)=0.03/0.31 [ both read off the contingency table ]
=0.0968
Jeremy can choose his outfit in following ways:
2 ways to select a shirt
2 ways to select a pant
2 ways to select socks
3 ways to select the footwear.
Total number of ways to select the dress = 2 x 2 x 2 x 3 = 24 ways
Jeremy will select an outfit that includes flip-flops, argyle socks and denim pants. The shirt is not specified, so the shirt can be any.
So there are 2 ways to select a shirt, 1 way to select the pant, socks and footwear. So Jeremy can select the desired outfit in 2 ways.
Thus, the probability that Jeremy will select an outfit that includes flip-flops, argyle socks and denim pants = 2/24 = 1/12
let the original price be x.
then,
x- 25% of x= 24
x- 25x/100 = 24
x- x/4=24
3x/4=24
3x= 96
x= 32
in short...the original price= 32 dollars
