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3 years ago

Which one is this please answer it and get thanks from me if ur right

Mathematics

1 answer:

mote1985 [20]3 years ago

4 0

♡ The Question ♡

- Which of the following is equivalent to the power shown below? 8^4

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

☆ The Answer ☆

- Your answer should be C!

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♡ The Explanation/Step-By-Step ♡

- When your power is being shown as 8^4, this can be represented as 'Eight four times.' This means it could be, 8, 8, 8, 8. Hope this helps!

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☆ Tips ☆

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Does the point (-9,-4) satisfy the equation y = x + 5?

ozzi

Answer:

Yes it satisfies the equation

Step-by-step explanation:

Let, P(x,y) = (-9,-4)

Then, x = -9

y = -4

if we use this value in the equation, we will get L.S = R.S ;(-4 = -9 + 5)

So, the point satisfies the equation

Hope you have understood this

Pls mark my answer as the brainliest

5 0

3 years ago

Solve for b. (g+l)b=n

denis23 [38]

Answer:

b = ---------

(g+l)

Step-by-step explanation:

We need to isolate b. Starting from (g+l)b=n, we divide both sides by (g+l), obtaining

b = ---------

(g+l)

7 0

3 years ago

Hurry ill give brainiest if u help me

grin007 [14]

The y-intercept should be closer to ten.

3 0

3 years ago

Read 2 more answers

The water level at your dock is 5 ft above sea level. The tide goes out and the water decreases by 8 ft. What integer represents

Tanya [424]

Answer:

-3

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid

Artist 52 [7]

Check the picture below. Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm². Also, recall, the base is a square, thus, length = width = x.

$\bf \textit{volume of a rectangular prism}\\\\
V=lwh\quad 
\begin{cases}
l = length\\
w=width\\
h=height\\
-----\\
w=l=x
\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\
-------------------------------\\\\
\textit{surface area}\\\\
S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h
\\\\\\
\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\
-------------------------------\\\\
V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3$

so.. that'd be the V(x) for such box, now, where is the maximum point at?

$\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2
\\\\\\
\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100
\\\\\\
x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}$

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it. Check the second picture below.

so, the volume will then be at $\bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3$

6 0

3 years ago