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miss Akunina [59]
4 years ago
5

2 . At what point ( s ) do these graphs intersect ? y = x2 + 3x - 5 y = 4x + 1 Seth's solution : y = x2 + 3x - 5 y = 4x + 1 x2 +

3x - 5 = 4x + 1 x ? - X - 6 = 0 ( x - 3 ) ( x + 2 ) - 0 x = 3 and x = -2 The graphs intersect at . ( - 20 ) and ( 3,0 ) . Is Seth's solution correct ? Explain . Answer :

Mathematics
2 answers:
garri49 [273]4 years ago
8 0

Answer:

\boxed{\mathrm{view \: explanation}}

Step-by-step explanation:

No, Seth’s solution is wrong.

He plugged the y-values as 0, which is wrong.

y = 4x + 1

Plug x as -2 and 3.

y = 4(-2) + 1

y = -8 + 1

y = -7

When x=-2, y=-7. The solution is (-2, -7).

y = 4(3) + 1

y = 12 + 1

y = 13

When x=3, y=13. The solution is (3, 13).

The graphs intersect at (-2, -7) and (3, 13).

Mariulka [41]4 years ago
4 0
Yes seths solution is correct because y=x2+3x-
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