Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
The normal rule to remember is 68-95-99.7, i.e. plus or minus three sigma corresponds to 99.7% of the probability. That leaves 0.3% in the two tails, or 0.15% in the tail above 3 sigma.
Answer: 0.15%
the second duckling is wandering by 2.6 units distance than the first duckling .
<u>Step-by-step explanation:</u>
Here we have , Two ducklings wander away from the nest while their mother is away. The first duckling's displacement (distance and direction) from the nest is (12,5) The second duckling's displacement is (13,-8) . We need to find How much farther did the second duckling wander than the first duckling. Let's find out:
Let a = (12,5) and b =(13,-8)
The distance each duckling wandered is the magnitude of its displacement vector. Therefore, the expression Distance second duck wandered is given by :
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Therefore , the second duckling is wandering by 2.6 units distance than the first duckling .
Answer:
350 mL of water
Step-by-step explanation:
Well she starts with 200mL of water and there is 800 mL of acid of water.
She drains 100 mL of acid and adds 100 mL of water so there is 300 mL of water.
And she stirs meaning the compounds have mixed.
Then she drains 100 mL and she they are mixed she drains half of acid and half of water so she has 250 mL of water.
The she adds 100 mL of water so now there’s 350 mL of water left.
The answer is C.50. That is the answer.