The answer is one million! Hope this helps!
Answer:
a) 0.778
b) 0.9222
c) 0.6826
d) 0.3174
e) 2 drivers
Step-by-step explanation:
Given:
Sample size, n = 5
P = 40% = 0.4
a) Probability that none of the drivers shows evidence of intoxication.
![P(x=0) = ^nC_x P^x (1-P)^n^-^x](https://tex.z-dn.net/?f=%20P%28x%3D0%29%20%3D%20%5EnC_x%20P%5Ex%20%281-P%29%5En%5E-%5Ex)
![P(x=0) = ^5C_0 (0.4)^0 (1-0.4)^5^-^0](https://tex.z-dn.net/?f=P%28x%3D0%29%20%3D%20%5E5C_0%20%20%280.4%29%5E0%20%281-0.4%29%5E5%5E-%5E0)
![P(x=0) = ^5C_0 (0.4)^0 (0.60)^5](https://tex.z-dn.net/?f=%20P%28x%3D0%29%20%3D%20%5E5C_0%20%280.4%29%5E0%20%280.60%29%5E5)
b) Probability that at least one of the drivers shows evidence of intoxication would be:
P(X ≥ 1) = 1 - P(X < 1)
c) The probability that at most two of the drivers show evidence of intoxication.
P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)
d) Probability that more than two of the drivers show evidence of intoxication.
P(x>2) = 1 - P(X ≤ 2)
e) Expected number of intoxicated drivers.
To find this, use:
Sample size multiplied by sample proportion
n * p
= 5 * 0.40
= 2
Expected number of intoxicated drivers would be 2
Answer: the value of the car in 2019 is $5269
Step-by-step explanation:
It loses 12% of its value every year. This means that the value of the car is decaying exponentially. We would apply the formula for exponential decay which is expressed as
A = P(1 - r)^t
Where
A represents the value of the car after t years.
t represents the number of years.
P represents the initial value of the car.
r represents rate of decay.
From the information given,
P = $21500
r = 12% = 12/100 = 0.12
t = 2019 - 2008 = 11 years
Therefore
A = 21500(1 - 0.12)^11
A = 21500(0.88)^11
A = 5269
Answer:
$55.50
Step-by-step explanation:
150 (0.37) = 55.5
Step-by-step explanation:
hope it is helpful to you