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2 years ago

11

A cone has a diameter of 8ft and height of 3ft. What’s the volume?

2 answers:

stepladder [879]2 years ago

7 0

Step-by-step explanation:

1/3 πr²h

Given

diameter (d) = 8ft

radius (r) = d/2 = 8/2 = 4 ft

height (h) = 3 ft

Volume of cone

$\frac{1}{3} \times \pi {r}^{2} h$

$\frac{1}{3} \times 3.14 \times {4}^{2} \times 3$

$\frac{150.72}{3}$

=50.24 ft³

Gennadij [26K]2 years ago

5 0

The cone formula is V=1/3(pi*r^2)h, plug in what you know 150pi=1/3(pi*r^2)8.

Multiply both sides by 3: 450pi=(pi*r^2)8

Divide by 8: 56.25pi=pi*r^2

Divide by pi: 56.25=r^2

Square root both sides: 7.5=r

Multiply by 2 to find diameter: d=15

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If sin A = 3/4, then the value of tan A

Schach [20]

$sinA=\frac{3}{4}$ ⇒ ∠A ≈ 49°

tanA ≈ 1.15

ok done. Thank to me :>

8 0

2 years ago

The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi

storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

$V = \frac{1}{3}\pi r^{2}h$

Differentiate the equation with respect to time t, such that

$\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)$

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)$

To differentiate the product,

Let r² = u, so that

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)$

Then, using product rule

$\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]$

Since $u = r^{2}$

Then, $\frac{du}{dr} = 2r$

Using the Chain's rule

$\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}$

∴ $\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]$

Then,

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

Now,

From the question

$\frac{dr}{dt} = 7 m/min$

$\frac{dV}{dt} = 236 m^{3}/min$

At the instant when $r = 99 m$

and $V = 180 m^{3}$

We will determine the value of h, using

$V = \frac{1}{3}\pi r^{2}h$

$180 = \frac{1}{3}\pi (99)^{2}h$

$180 \times 3 = 9801\pi h$

$h =\frac{540}{9801\pi }$

$h =\frac{20}{363\pi }$

Now, Putting the parameters into the equation

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

$236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]$

$236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]$

$708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}$

$708 = 30790.75 \frac{dh}{dt} + 76.36$

$708 - 76.36 = 30790.75\frac{dh}{dt}$

$631.64 = 30790.75\frac{dh}{dt}$

$\frac{dh}{dt}= \frac{631.64}{30790.75}$

$\frac{dh}{dt} = 0.021 m/min$

Hence, the rate of change of the height is 0.021 meters per minute.

3 0

2 years ago

There are 20 deer per 2 square miles In

sladkih [1.3K]

Answer:

594,250 (a)

Step-by-step explanation:

2 sq. miles = 20 deers

1 sq. mile = 20÷2 = 10

59,425 sq. miles = 59,425×10

= 594,250

8 0

2 years ago

Please answer number 71

VLD [36.1K]

A rotation on its axis of 180 degrees

4 0

3 years ago

I am so confused. Can anyone help me??

natita [175]

Answer:

bro! im in 7th grade i would try to help but im very stupid sorry for the dissopiontment

Step-by-step explanation:

8 0

2 years ago