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4 years ago

A square with an area of 64 in2 is rotated to form a cylinder. What is the radius of the cylinder?

1 answer:

5 0

The area of the square is calculated through the equation,

Area = e²

where e is the measure of sides.

From the given,

64 = e²
e = sqrt 64 = 8 inches

The length of the side of the square rotated to form the cylinder is the diameter of the base of the cylinder. To get the radius, we divide the diameter by 2.

radius = 8 inches / 2 = 4 inches

Thus, the radius of the cylinder is equal to <em>4 inches</em>.

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The plans for a new ammusement park were laid out on the first quadrant of a coordinate plane. The entrance to the roller coaste

Solnce55 [7]

The first step is to determine the distance between the points, (1,1) and (7,9)

We would find this distance by applying the formula shown below

$\begin{gathered} \text{Distance = }\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ \text{From the graph, } \\ x1\text{ = 1, y1 = 1} \\ x2\text{ = 7, y2 = 9} \\ \text{Distance = }\sqrt[]{(7-1)^2+(9-1)^2} \\ \text{Distance = }\sqrt[]{6^2+8^2}\text{ = }\sqrt[]{100} \\ \text{Distance = 10} \end{gathered}$

Distance = 10 units

If one unit is 70 meters, then the distance between both entrances is

70 * 10 = 700 meters

4 0

1 year ago

write the equation of a line that includes the point (1,5) and has a slope of 3 in slope intercept form.

lina2011 [118]

Y=3x+? (1,5)
5=3(1)+?
5=3+?

y=3x+2

7 0

3 years ago

Hey guys can u pls help me.

nadya68 [22]

Answer:

It's b

it's kinda hard to explain but it ends up showing .7x.5 on the example, so your answer is B

4 0

3 years ago

Read 2 more answers

How do I solve part b?

Minchanka [31]

Answer:

$x \approx 1.4$

Step-by-step explanation:

This problem gives one the following equation to model the graph of a line: ( $y=x^2-2$ ). The problem asks one to find the value of (x) when (y=0). Rather than using the graph, an easier way to solve this problem is to substitute (0) in for the value of (y) and then solve for (x) using inverse operations.

$y=x^2-2\\$

Substitute,

$0=x^2-2$

Inverse operations,

$0=x^2-2\\\\2=x^2\\\\\sqrt{2}=x$

Round:

$x \approx 1.4$

As one can see on the graph, this result is very close to the value at which the graph intersects the (x) axis. Thus, one can conclude that (x) does indeed approximately equal (1.4)

6 0

3 years ago

andrey2020 [161]

Answer:

Do you want the perimeter of this shape?

5 0

3 years ago